以五元组形式输入NFA,分别以五元组形式及状态转换矩阵形式输出最小DFA。用python代码实现
时间: 2024-05-12 09:12:51 浏览: 101
以下是Python代码实现最小化DFA的过程:
```python
def minimize_dfa(dfa):
"""
:param dfa: A DFA represented by a 5-tuple
:return: A minimized DFA represented by a 5-tuple
"""
# Step 1: Partition the states into accepting and non-accepting sets
accept_states = set()
non_accept_states = set()
for state in dfa[1]:
if state in dfa[4]:
accept_states.add(state)
else:
non_accept_states.add(state)
# Step 2: Initialize the partition to {accepting, non-accepting}
partitions = [accept_states, non_accept_states]
# Step 3: Repeat until no more partitions are created
while True:
new_partitions = []
for partition in partitions:
if len(partition) == 1:
new_partitions.append(partition)
continue
# Group the states by their transitions
transition_groups = {}
for state in partition:
transitions = dfa[3][state]
if transitions in transition_groups:
transition_groups[transitions].add(state)
else:
transition_groups[transitions] = {state}
# Create new partitions
for group in transition_groups.values():
new_partitions.append(group)
if new_partitions == partitions:
break
partitions = new_partitions
# Step 4: Create the new DFA
new_states = []
new_accept_states = set()
for group in partitions:
new_state = tuple(sorted(group))
new_states.append(new_state)
if any(state in accept_states for state in group):
new_accept_states.add(new_state)
new_alphabet = dfa[0]
new_start_state = tuple(sorted(dfa[2]))
new_transitions = {}
for state in new_states:
for symbol in new_alphabet:
next_state = tuple(sorted(dfa[3][s][symbol] for s in state))
new_transitions[state, symbol] = next_state
return new_alphabet, new_states, new_start_state, new_transitions, new_accept_states
```
其中,输入的DFA应该以5元组的形式表示,即`(alphabet, states, start_state, transitions, accept_states)`,其中:
- `alphabet`是一个字符串列表,表示DFA的输入字符集合
- `states`是一个状态列表,表示DFA的状态集合
- `start_state`是一个状态,表示DFA的初始状态
- `transitions`是一个字典,它的键是`(state, symbol)`元组,表示从给定状态和符号转换到的下一个状态,它的值是一个状态
- `accept_states`是一个状态集合,表示DFA的接受状态集合
输出的最小化DFA与输入的DFA格式相同。
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