select u_i.uid as uid, count(distinct act_month) as act_month_total, count(distinct case when year(act_time) = 2021 then act_day end) as act_days_2021, count(distinct case when year(act_time) = 2021 and tag = 'exam' then act_day end) as act_days_2021_exam, count(distinct case when year(act_time) = 2021 and tag = 'question' then act_day end) as act_days_2021_question from user_info u_i left join (select uid, start_time as act_time, date_format(start_time, '%Y%m') as act_month, date_format(start_time, '%Y%m%d') as act_day, 'exam' as tag from exam_record union all select uid, submit_time as act_time, date_format(submit_time, '%Y%m') as act_month, date_format(submit_time, '%Y%m%d') as act_day, 'question' as tag from practice_record ) exam_and_practice on exam_and_practice.uid = u_i.uid where u_i.level >= 6 group by uid order by act_month_total desc, act_days_2021 desc

这是一条 SQL 查询语句，用于查询用户的活跃度。具体来说，它会统计用户在不同时间段内参加考试或练习的次数，并按照总活跃度和2021年活跃度排序。其中，act_month_total 表示用户参加考试或练习的活跃月份数，act_days_2021 表示用户在2021年参加考试或练习的天数，act_days_2021_exam 和 act_days_2021_question 分别表示用户在2021年参加考试或练习、且标记为“exam”或“question”的天数。该语句使用了左连接和子查询等高级语法，适用于较大规模的数据查询。

相关问题

select t1.month_id, count(distinct case when t1.offer_type_name='主套餐' then offer_name end) aa, count(distinct case when t1.offer_type_name='促销' then offer_name end) bb, count(distinct case when t1.offer_type_name='可选包' then offer_name end) cc, count(distinct case when t2.offer_type_name='主套餐' then offer_name end) aaa, count(distinct case when t2.offer_type_name='促销' then offer_name end) bbb, count(distinct case when t2.offer_type_name='可选包' then offer_name end) ccc, from zone_crmchk.dwd_sum_zhuliuxxsc t1 left join zone_crmchk.dwd_sum_zhuliuxxsc t2 on t2.month < t1.month group by t1.month, count(distinct case when offer_type_name='主套餐' then offer_name end) aa, count(distinct case when offer_type_name='促销' then offer_name end) bb, count(distinct case when offer_type_name='可选包' then offer_name end) cc

根据您提供的 SQL 查询语句，我发现其中存在一个逗号(,)出现在了 FROM 子句之后，这是一个语法错误。您需要将逗号(,)删除，同时将查询语句修改为如下形式：

SELECT
    t1.month_id, 
    COUNT(DISTINCT CASE WHEN t1.offer_type_name='主套餐' THEN offer_name END) aa, 
    COUNT(DISTINCT CASE WHEN t1.offer_type_name='促销' THEN offer_name END) bb, 
    COUNT(DISTINCT CASE WHEN t1.offer_type_name='可选包' THEN offer_name END) cc, 
    COUNT(DISTINCT CASE WHEN t2.offer_type_name='主套餐' THEN offer_name END) aaa, 
    COUNT(DISTINCT CASE WHEN t2.offer_type_name='促销' THEN offer_name END) bbb, 
    COUNT(DISTINCT CASE WHEN t2.offer_type_name='可选包' THEN offer_name END) ccc
FROM 
    zone_crmchk.dwd_sum_zhuliuxxsc t1 
    LEFT JOIN zone_crmchk.dwd_sum_zhuliuxxsc t2 ON t2.month < t1.month 
GROUP BY 
    t1.month_id, 
    COUNT(DISTINCT CASE WHEN offer_type_name='主套餐' THEN offer_name END), 
    COUNT(DISTINCT CASE WHEN offer_type_name='促销' THEN offer_name END), 
    COUNT(DISTINCT CASE WHEN offer_type_name='可选包' THEN offer_name END);

这样修改后，查询语句应该就能正确执行了。

select a.month_id, sum(b.aa) aa, sum(b.bb) bb, sum(b.cc) cc, '今年往月新增订购' as A from ( select month_id, sum(aa) aa,sum(bb) bb,sum(cc) cc from ( select month_id , count(distinct case when offer_type_name='主套餐' then offer_name end) aa, count(distinct case when offer_type_name='促销' then offer_name end) bb, count(distinct case when offer_type_name='可选包' then offer_name end) cc, from dwd_sum_zhuliuxxsc where substring(crt_version,1,4)='2023' group by month_id ) ptuser group by month_id ) a join ( select month_id,sum(aa) aa,sum(bb) bb,sum(cc) cc from ( select month_id , count(distinct case when offer_type_name='主套餐' then offer_name end) aa, count(distinct case when offer_type_name='促销' then offer_name end) bb, count(distinct case when offer_type_name='可选包' then offer_name end) cc, from dwd_sum_zhuliuxxsc where substring(crt_version,1,4)='2023' group by month_id ) ptuser group by month_id ) b on a.month_id >= b.month_id group by a.month_id order by a.month_id;如何改成计算今年往月(不包含本月)的统计

您可以将子查询中的 `where substring(crt_version,1,4)='2023'` 改为 `where year(crt_version) = year(current_date()) and month_id < month(current_date())`，这样就只会统计今年往月的数据（不包含本月）。修改后的 SQL 语句如下：

select a.month_id, 
       sum(b.aa) aa, 
       sum(b.bb) bb, 
       sum(b.cc) cc, 
       '今年往月新增订购' as A 
from (
    select month_id, sum(aa) aa,sum(bb) bb,sum(cc) cc
    from (
        select month_id,
               count(distinct case when offer_type_name='主套餐' then offer_name end) aa,
               count(distinct case when offer_type_name='促销' then offer_name end) bb,
               count(distinct case when offer_type_name='可选包' then offer_name end) cc
        from dwd_sum_zhuliuxxsc
        where year(crt_version) = year(current_date()) and month_id < month(current_date())
        group by month_id
    ) ptuser
    group by month_id
) a
join (
    select month_id,sum(aa) aa,sum(bb) bb,sum(cc) cc
    from (
        select  month_id,
                count(distinct case when offer_type_name='主套餐' then offer_name end) aa,
                count(distinct case when offer_type_name='促销' then offer_name end) bb,
                count(distinct case when offer_type_name='可选包' then offer_name end) cc
        from dwd_sum_zhuliuxxsc
        where year(crt_version) = year(current_date()) and month_id < month(current_date())
        group by month_id
    ) ptuser
    group by month_id
) b
on a.month_id >= b.month_id
group by a.month_id
order by a.month_id;

注意，这里的 `current_date()` 函数是 MySQL 中获取当前日期的函数，如果您使用的是其他数据库，获取当前日期的函数可能有所不同。