N=int(input()) for i in range(1,N+1): if '0' in str(i): continue if all(i % int(digit) == 0 for digit in str(i)): print(i)这个程序来求自除数哪里有错误
时间: 2024-02-23 21:00:59 浏览: 22
这个程序存在一个语法错误,即在第一行中没有使用任何变量名,程序无法运行。应该先声明一个变量N并将输入的值赋值给它,例如:
```
N = int(input())
```
此外,该程序有一个逻辑错误:当数字中包含0时,程序会跳过这个数字而不进行自除数的判断,这是不正确的。因为0除以任何数都是0,所以包含0的数字一定不是自除数。所以应该将第2行代码修改为:
```
if '0' in str(i):
continue
```
最终的程序应该是这样的:
```
N = int(input())
for i in range(1, N+1):
if '0' in str(i):
continue
if all(i % int(digit) == 0 for digit in str(i)):
print(i)
```
相关问题
请优化这段代码:def continuous(n): flag = 1 for i in range(len(n)): if i == 0: continue elif i == len(n)-1: break else: if n[i-1] == n[i] and n[i] == n[i+1]: flag = 0 return flag def subtraction(n): flag = 1 for i in range(len(n)): if flag == 0: break elif i == 0: continue elif i == len(n)-1: break else: if abs(int(n[i-1])-int(n[i])) > 4 or abs(int(n[i])-int(n[i+1])) > 4 : flag = 0 break return flag def all(n): flag = 1 for i in range(len(n)): if int(n[i]) > 6: flag = 0 break return flag def judge(n): flag = 1 a = continuous(n) b = subtraction(n) c = all(n) if a != 1 or b != 1 or c != 1: flag = 0 return flag N = int(input()) n = 0 while n < N: t1, t2 = map(str,input().split()) if judge(t1) != 1 or len(t1) != 6: print("输入门票有误") break if judge(t2) != 1 or len(t2) != 6: print("输入门票有误") break t1,t2 = int(t1), int(t2) for i in range(t1,t2+1): print("{:6d}".format(i).replace(" ","0")) print("") n += 1
以下是对代码进行的一些优化:
1. 在 `continuous`、`subtraction` 和 `all` 函数中,可以使用 `any` 和 `all` 函数来简化代码:
```python
def continuous(n):
return not any(n[i-1] == n[i] == n[i+1] for i in range(1, len(n)-1))
def subtraction(n):
return all(abs(int(n[i-1])-int(n[i])) <= 4 and abs(int(n[i])-int(n[i+1])) <= 4 for i in range(1, len(n)-1))
def all(n):
return all(int(digit) <= 6 for digit in n)
```
2. 在 `judge` 函数中,可以直接将三个子函数的返回值相乘,来判断是否所有条件都满足:
```python
def judge(n):
return all((continuous(n), subtraction(n), all(n)))
```
3. 在主函数中,可以直接使用 `try-except` 来捕获输入门票有误的情况,而不需要在每个判断中都输出错误信息。此外,可以使用 `range` 函数的 step 参数来避免使用 `while` 循环:
```python
N = int(input())
for n in range(N):
try:
t1, t2 = map(str,input().split())
t1,t2 = int(t1), int(t2)
if not (6 <= len(t1) <= 6 and 6 <= len(t2) <= 6 and judge(t1) and judge(t2)):
raise ValueError("输入门票有误")
for i in range(t1,t2+1):
print(f"{i:06}")
print()
except ValueError as e:
print(e)
```
在这个版本的代码中,主函数中使用了 `try-except` 来捕获 `ValueError` 异常,如果输入的门票有误,则会输出错误信息,否则直接进行门票编号的生成和输出。
将这个代码换成c语言panduan='true' sum=[0,0,0] m=input().split() text=[] for i in range(5): text.append(input().split()) n=input().split() sum[0]=int(m[0]) sum[1]=int(m[1]) sum[2]=int(m[2]) for j in range(5): text[j].append(int(text[j][1])-int(text[j][4])) text[j].append(int(text[j][2])-int(text[j][5])) text[j].append(int(text[j][3])-int(text[j][6])) if int(n[1])>int(m[0]) or int(n[2])>int(m[1]) or int(n[3])>int(m[2]): panduan='false' for i in range(5): sum[0]+=int(text[i][4]) sum[1]+=int(text[i][5]) sum[2]+=int(text[i][6]) if str(n[0])==str(text[i][0]): if int(n[1])<=text[i][7] and int(n[2])<=text[i][8] and int(n[3])<=text[i][9]: text[i][4]=int(text[i][4])+int(n[1]) text[i][5]=int(text[i][5])+int(n[2]) text[i][6]=int(text[i][6])+int(n[3]) text[i][7]=int(text[i][7])-int(n[1]) text[i][8]=int(text[i][8])-int(n[2]) text[i][9]=int(text[i][9])-int(n[3]) m[0]=int(m[0])-int(n[1]) m[1]=int(m[1])-int(n[2]) m[2]=int(m[2])-int(n[3]) else: panduan='false' for j in range(5): for i in range(5): if text[i][7]==0 and text[i][8]==0 and text[i][9]==0: continue elif int(m[0])>=text[i][7] and int(m[1])>=text[i][8] and int(m[2])>=text[i][9]: m[0]=int(m[0])+int(text[i][4]) m[1]=int(m[1])+int(text[i][5]) m[2]=int(m[2])+int(text[i][6]) text[i][7]=0 text[i][8]=0 text[i][9]=0 if m[0]!=sum[0] or m[1]!=sum[1] or m[2]!=sum[2]: panduan='false' print(panduan)
把这段 Python 代码转换成 C 语言的代码如下:
#include <stdio.h>
#include <stdbool.h>
#include <stdlib.h>
#include <string.h>
#define MAX_LEN 10
int main() {
char panduan[] = "true";
int sum[3] = {0, 0, 0};
char m[MAX_LEN];
char text[5][10];
char n[4];
fgets(m, MAX_LEN, stdin);
char *token = strtok(m, " ");
sum[0] = atoi(token);
token = strtok(NULL, " ");
sum[1] = atoi(token);
token = strtok(NULL, " ");
sum[2] = atoi(token);
for (int i = 0; i < 5; i++) {
fgets(text[i], MAX_LEN, stdin);
token = strtok(text[i], " ");
for (int j = 1; j < 7; j++) {
token = strtok(NULL, " ");
}
text[i][7] = atoi(strtok(NULL, " ")) - atoi(strtok(NULL, " "));
text[i][8] = atoi(strtok(NULL, " ")) - atoi(strtok(NULL, " "));
text[i][9] = atoi(strtok(NULL, " ")) - atoi(strtok(NULL, " "));
}
fgets(n, 4, stdin);
token = strtok(n, " ");
char name[MAX_LEN];
strcpy(name, token);
if (atoi(strtok(NULL, " ")) > sum[0] || atoi(strtok(NULL, " ")) > sum[1] || atoi(strtok(NULL, " ")) > sum[2]) {
strcpy(panduan, "false");
}
for (int i = 0; i < 5; i++) {
sum[0] += atoi(strtok(text[i], " "));
sum[1] += atoi(strtok(NULL, " "));
sum[2] += atoi(strtok(NULL, " "));
if (strcmp(name, strtok(NULL, " ")) == 0) {
int a = atoi(strtok(NULL, " "));
int b = atoi(strtok(NULL, " "));
int c = atoi(strtok(NULL, " "));
if (a <= atoi(&text[i][7]) && b <= atoi(&text[i][8]) && c <= atoi(&text[i][9])) {
sprintf(&text[i][4], "%d", atoi(&text[i][4]) + a);
sprintf(&text[i][5], "%d", atoi(&text[i][5]) + b);
sprintf(&text[i][6], "%d", atoi(&text[i][6]) + c);
sprintf(&text[i][7], "%d", atoi(&text[i][7]) - a);
sprintf(&text[i][8], "%d", atoi(&text[i][8]) - b);
sprintf(&text[i][9], "%d", atoi(&text[i][9]) - c);
sum[0] -= a;
sum[1] -= b;
sum[2] -= c;
} else {
strcpy(panduan, "false");
}
}
}
for (int j = 0; j < 5; j++) {
for (int i = 0; i < 5; i++) {
if (text[i][7] == '0' && text[i][8] == '0' && text[i][9] == '0') {
continue;
} else if (atoi(&m[0]) >= atoi(&text[i][7]) && atoi(&m[2]) >= atoi(&text[i][8]) && atoi(&m[2]) >= atoi(&text[i][9])) {
sum[0] += atoi(&text[i][4]);
sum[1] += atoi(&text[i][5]);
sum[2] += atoi(&text[i][6]);
sprintf(&m[0], "%d", atoi(&m[0]) + atoi(&text[i][7]));
sprintf(&m[1], "%d", atoi(&m[1]) + atoi(&text[i][8]));
sprintf(&m[2], "%d", atoi(&m[2]) + atoi(&text[i][9]));
sprintf(&text[i][7], "%d", 0);
sprintf(&text[i][8], "%d", 0);
sprintf(&text[i][9], "%d", 0);
}
}
}
if (sum[0] != atoi(&m[0]) || sum[1] != atoi(&m[1]) || sum[2] != atoi(&m[2])) {
strcpy(panduan, "false");
}
printf("%s", panduan);
return 0;
}
注意,这里使用了 C 语言的字符串处理函数 strtok 和 sprintf,需要在头文件中包含 stdlib.h 和 string.h。同时,Python 中的列表在 C 中用二维数组来表示。另外,Python 中的字符串与数字可以互相转换,但是在 C 中需要使用 atoi 和 sprintf 等函数来实现。
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