Prepare a 5-minute video to show the execution of your program on the lab board followed by an explanation of your code in Keil uVision (See Scenario 1 below). You may also discuss the testing/simulation/debugging of your program. This video should be submitted on QMPlus (60%). Please begin with a clear camera view of yourself, introducing your name (in Pinyin) and QMUL student ID. Scenario 1: Use the RealTerm serial terminal to transmit you name in Pinyin in CAPITAL letters. Upon receiving the first letter, the programme should start sending the Morse code of incoming letters First-In-First-Out.分析下需求

根据你的问题，我理解你是在询问如何执行一个程序并在Keil uVision中解释代码，然后制作一个展示程序执行和代码解释的5分钟视频，并且视频需要包括测试、仿真和调试的过程。具体要求是使用RealTerm串行终端发送大写拼音姓名，接收到第一个字母后，程序应该按照先进先出的原则发送对应字母的莫尔斯码。视频需要包括自我介绍和学生ID，并在开始展示之前保持清晰的摄像头视角。

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error execution phase wait-control-plane: couldn't initialize a Kubernetes cluster To see the stack trace of this error execute with --v=5 or higher

这个错误提示说明在执行 wait-control-plane 阶段时，Kubernetes 集群无法初始化。您可以通过使用 --v=5 或更高级别的参数来查看此错误的堆栈跟踪。此外，您还可以检查 Kubernetes 集群的配置和状态，以确保其正常运行。可能需要检查 Kubernetes 集群的网络连接、节点状态以及 kubelet 和 kube-proxy 的配置等方面。

The lab computer will execute a program, instruction by instruction, when you give the command step in the console window. Use this command and execute the program step by step, and inspect what happens with the registers and program counter after each step. Try to record and explain the execution of two of the example programs above

Sure, let me explain and record the execution of two example programs step by step.

Example 1: Addition Program

Code:

LOAD R1, 5
LOAD R2, 7
ADD R3, R1, R2

Execution Steps:
1. The program counter (PC) starts at 0, which points to the first instruction.
2. The instruction `LOAD R1, 5` is executed, which loads the value `5` into register `R1`.
3. The PC is incremented to 1, which points to the next instruction.
4. The instruction `LOAD R2, 7` is executed, which loads the value `7` into register `R2`.
5. The PC is incremented to 2, which points to the next instruction.
6. The instruction `ADD R3, R1, R2` is executed, which adds the values in registers `R1` and `R2`, and stores the result in register `R3`.
7. The PC is incremented to 3, which points to the next instruction.
8. The program terminates.

Registers:
- Before execution:

R1: 0
R2: 0
R3: 0

- After execution:

R1: 5
R2: 7
R3: 12

Example 2: Loop Program

Code:

LOAD R1, 10
LOAD R2, 0
LOOP:
ADD R2, R2, 1
SUB R1, R1, 1
BNE R1, 0, LOOP

Execution Steps:
1. The program counter (PC) starts at 0, which points to the first instruction.
2. The instruction `LOAD R1, 10` is executed, which loads the value `10` into register `R1`.
3. The PC is incremented to 1, which points to the next instruction.
4. The instruction `LOAD R2, 0` is executed, which loads the value `0` into register `R2`.
5. The PC is incremented to 2, which points to the next instruction.
6. The label `LOOP` is encountered, which does not affect the PC.
7. The instruction `ADD R2, R2, 1` is executed, which adds `1` to the value in register `R2`.
8. The PC is incremented to 3, which points to the next instruction.
9. The instruction `SUB R1, R1, 1` is executed, which subtracts `1` from the value in register `R1`.
10. The PC is incremented to 4, which points to the next instruction.
11. The instruction `BNE R1, 0, LOOP` is executed, which checks if the value in register `R1` is equal to `0`. Since it is not, the PC is set to the address of the label `LOOP`.
12. The program returns to step 6 and repeats the loop until the value in register `R1` becomes `0`.
13. When the loop terminates, the PC is incremented to 5, which points to the next instruction.
14. The program terminates.

Registers:
- Before execution:

R1: 0
R2: 0

- After execution:

R1: 0
R2: 10