编程，输入 n(3<n<=10)个职工的编号、姓名、基本工资、职务工资，输 出其中“基本工资+职务工资”最少和最多的职工姓名。 输入输出示例： n=5 1,林宏，1800,600 2,李涛，1700,550 3,王钢，2100,750 4,周航，1500,450 5,金明，2300,850 基本工资+职务工资最不的是：周航 基本工资+职务工资最多的是：金明 6．编程，建立一个有 n(3<n<=10)个学生成绩的结构记录，包括学号、姓名 和 3 门成绩，输出总分最高学生的姓名和总分。用c语言

以下是第一题的示例代码：

#include <stdio.h>
#include <string.h>

struct Employee {
    int id;
    char name[20];
    int basicSalary;
    int positionSalary;
};

int main() {
    int n, minIndex, maxIndex, minSalary = 0x7fffffff, maxSalary = -0x7fffffff;
    struct Employee employees[10];
    printf("Enter the number of employees (3<=n<=10): ");
    scanf("%d", &n);
    for (int i = 0; i < n; i++) {
        printf("Enter employee #%d's id, name, basicSalary and positionSalary: ", i+1);
        scanf("%d %s %d %d", &employees[i].id, employees[i].name, &employees[i].basicSalary, &employees[i].positionSalary);
        int totalSalary = employees[i].basicSalary + employees[i].positionSalary;
        if (totalSalary < minSalary) {
            minSalary = totalSalary;
            minIndex = i;
        }
        if (totalSalary > maxSalary) {
            maxSalary = totalSalary;
            maxIndex = i;
        }
    }
    printf("The employee with the lowest total salary is: %s\n", employees[minIndex].name);
    printf("The employee with the highest total salary is: %s\n", employees[maxIndex].name);
    return 0;
}

输入职工的信息，然后使用循环计算出每个职工的总工资，同时记录下最少和最多的职工的索引。最后输出这两个职工的姓名。

以下是第二题的示例代码：

#include <stdio.h>
#include <string.h>

struct Student {
    int id;
    char name[20];
    int score1;
    int score2;
    int score3;
};

int main() {
    int n, maxIndex, maxScore = -0x7fffffff;
    struct Student students[10];
    printf("Enter the number of students (3<=n<=10): ");
    scanf("%d", &n);
    for (int i = 0; i < n; i++) {
        printf("Enter student #%d's id, name, score1, score2 and score3: ", i+1);
        scanf("%d %s %d %d %d", &students[i].id, students[i].name, &students[i].score1, &students[i].score2, &students[i].score3);
        int totalScore = students[i].score1 + students[i].score2 + students[i].score3;
        if (totalScore > maxScore) {
            maxScore = totalScore;
            maxIndex = i;
        }
    }
    printf("The student with the highest total score is: %s\n", students[maxIndex].name);
    printf("The total score is: %d\n", maxScore);
    return 0;
}

输入学生的信息，然后使用循环计算出每个学生的总分数，同时记录下总分最高的学生的索引。最后输出这个学生的姓名和总分数。