在一个包名为DFAE和类名为DFAExample的Java程序中结合dfaRecognize函数分别实现24.E' → E 25. E → E + T | T 26. T → F | F * F 27. F → id
时间: 2023-06-23 19:08:11 浏览: 173
以下是一个可能的实现:
```java
package DFAE;
import java.util.Scanner;
public class DFAExample {
enum State {
START, // 初始状态
E, E_PLUS, T, T_TIMES, F, ID, ERROR, // 状态
FINAL // 终止状态
}
static State dfaRecognize(String input) {
State state = State.START;
int i = 0;
while (i < input.length()) {
char c = input.charAt(i);
switch (state) {
case START:
if (c == 'i') state = State.ID;
else if (c == '(') state = State.E;
else state = State.ERROR;
break;
case E:
if (c == 'i' || c == '(') state = State.E;
else if (c == '+') state = State.E_PLUS;
else state = State.ERROR;
break;
case E_PLUS:
if (c == 'i' || c == '(') state = State.T;
else state = State.ERROR;
break;
case T:
if (c == 'i' || c == '(') state = State.F;
else state = State.ERROR;
break;
case T_TIMES:
if (c == 'i' || c == '(') state = State.F;
else state = State.ERROR;
break;
case F:
if (c == 'i') state = State.ID;
else if (c == '(') state = State.E;
else state = State.ERROR;
break;
case ID:
if (c == 'i' || c == '(' || c == '+' || c == '*' || c == ')') state = State.FINAL;
else state = State.ERROR;
break;
default:
state = State.ERROR;
break;
}
i++;
}
if (state == State.START || state == State.ERROR) {
return State.ERROR;
} else {
return State.FINAL;
}
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("请输入一个字符串: ");
String input = scanner.nextLine();
State state = dfaRecognize(input);
if (state == State.FINAL) {
System.out.println("该字符串符合语法规则。");
} else {
System.out.println("该字符串不符合语法规则。");
}
}
}
```
在该程序中,我们使用了一个 `enum` 类型 `State` 表示 DFA 的状态。`dfaRecognize` 函数接受一个字符串作为输入,然后根据语法规则逐个字符地对输入字符串进行分析,最后返回字符串是否符合语法规则。`main` 函数则是一个简单的示例,用于从命令行输入一个字符串并输出结果。
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