用C语言代码实现从标准输入中读入两个多项式。且该多项式中各项的系数均为0或正整数,最高幂次不超过1000000。对于多项式 anxn + an-1xn-1+.... + a1x1 + a0x0 (n<=1000000)的表示方法如下: an n an-1 n-1 ... a1 1 a0 0 第一、二行读入第一个多项式。第一行,表示多项式的项数。紧接着下一行输入该多项式的每一项。相邻两个整数分别表示表达式中一项的系数和指数。在输入中只出现系数不为0的项。 第三、四行读入第二个多项式。将运算结果输出到屏幕。将系数不为0的项按指数从高到低的顺序输出,每次输出其系数和指数,均以一个空格分隔。在行的末尾也输出一个空格符,并且最后要求换行。使用链表并且空间复杂度为O(1)
时间: 2023-05-28 17:05:53 浏览: 70
【数据结构实验】用单链表实现多项式的计算(C语言)
```c
#include <stdio.h>
#include <stdlib.h>
typedef struct Node {
int coef; // 系数
int exp; // 指数
struct Node *next;
} Node, *Polynomial;
Polynomial create() { // 创建空链表
Polynomial p = (Polynomial)malloc(sizeof(Node));
p->next = NULL;
return p;
}
Polynomial read() { // 读入多项式
int n, coef, exp;
Polynomial p = create();
scanf("%d", &n);
while (n--) {
scanf("%d %d", &coef, &exp);
Polynomial q = (Polynomial)malloc(sizeof(Node));
q->coef = coef;
q->exp = exp;
q->next = NULL;
Polynomial t = p;
while (t->next && t->next->exp > exp) {
t = t->next;
}
if (t->next && t->next->exp == exp) {
t->next->coef += coef;
free(q);
} else {
q->next = t->next;
t->next = q;
}
}
return p;
}
void print(Polynomial p) { // 输出多项式
int flag = 0;
while (p->next) {
if (flag) {
printf(" ");
} else {
flag = 1;
}
printf("%d %d", p->next->coef, p->next->exp);
p = p->next;
}
printf("\n");
}
Polynomial add(Polynomial p1, Polynomial p2) { // 多项式相加
Polynomial p = create();
Polynomial t = p;
while (p1->next && p2->next) {
if (p1->next->exp > p2->next->exp) {
t->next = p1->next;
p1 = p1->next;
} else if (p1->next->exp < p2->next->exp) {
t->next = p2->next;
p2 = p2->next;
} else {
int coef = p1->next->coef + p2->next->coef;
if (coef) {
Polynomial q = (Polynomial)malloc(sizeof(Node));
q->coef = coef;
q->exp = p1->next->exp;
q->next = NULL;
t->next = q;
p1 = p1->next;
p2 = p2->next;
} else {
p1 = p1->next;
p2 = p2->next;
}
}
t = t->next;
}
if (p1->next) {
t->next = p1->next;
}
if (p2->next) {
t->next = p2->next;
}
return p;
}
int main() {
Polynomial p1 = read();
Polynomial p2 = read();
Polynomial p = add(p1, p2);
print(p);
return 0;
}
```
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