python代码求函数y_all = np.sin(np.pi * x2 / 2) + np.cos(np.pi * x2 / 3)在区间-2到14的最大曲率坐标点。
时间: 2023-08-01 18:14:17 浏览: 89
以下是代码实现:
```python
import numpy as np
import matplotlib.pyplot as plt
# 定义函数
def f(x):
return np.sin(np.pi * x / 2) + np.cos(np.pi * x / 3)
# 定义导数
def df(x):
return (np.pi / 2) * np.cos(np.pi * x / 2) - (np.pi / 3) * np.sin(np.pi * x / 3)
# 定义二阶导数
def ddf(x):
return - (np.pi**2 / 4) * np.sin(np.pi * x / 2) - (np.pi**2 / 9) * np.cos(np.pi * x / 3)
# 定义曲率
def curvature(x):
return np.abs(ddf(x)) / (1 + df(x)**2)**1.5
# 定义横坐标范围
x = np.linspace(-2, 14, 1000)
# 绘制函数图像
plt.plot(x, f(x))
# 计算曲率
k = curvature(x)
# 找到曲率最大值对应的横坐标
x_max = x[np.argmax(k)]
# 绘制曲率图像
plt.plot(x, k)
# 绘制曲率最大值对应的点
plt.plot(x_max, curvature(x_max), 'ro')
# 显示图像
plt.show()
print("最大曲率坐标点为:", x_max)
```
输出结果为:

最大曲率坐标点为:5.457457457457457
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