我需要一个贝叶斯优化的代码,拟合目标函数使用高斯过程,采样函数使用期望提高算法,不要调用高斯过程和贝叶斯的包,并书写足够的注释,在最后使用所写的算法优化z=sin2x+cos2y在取值空间上的最大值
时间: 2024-05-02 15:17:15 浏览: 74
matlab-基于高斯过程的Bayesian贝叶斯全局优化matlab仿真-源码
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好的,这里提供一个简单的贝叶斯优化代码,使用高斯过程进行目标函数的拟合,采样函数使用期望提高算法。注释已经添加在代码中。
```python
import numpy as np
# 目标函数
def target(x, y):
return np.sin(2 * x) + np.cos(2 * y)
# 高斯过程
class GaussianProcess:
def __init__(self, kernel, x, y):
self.kernel = kernel
self.x = x
self.y = y
self.K_inv = np.linalg.inv(kernel(x, x) + 1e-6 * np.eye(len(x)))
def predict(self, x_new):
k = self.kernel(self.x, x_new)
mu = k.T @ self.K_inv @ self.y
sigma = self.kernel(x_new, x_new) - k.T @ self.K_inv @ k
return mu, sigma
# 期望提高算法
def expected_improvement(mean, std, best):
z = (mean - best) / std
return (mean - best) * norm.cdf(z) + std * norm.pdf(z)
# 贝叶斯优化
def bayesian_optimization(kernel, acquisition, target, bounds, n_iter=10):
x_best = None
y_best = None
x_observed = []
y_observed = []
for i in range(n_iter):
# 采样函数
x_new = None
ei_best = None
for j in range(100):
x = np.random.uniform(bounds[:, 0], bounds[:, 1])
mu, sigma = gp.predict(x.reshape(1, -1))
ei = acquisition(mu, np.sqrt(sigma), y_best)
if ei_best is None or ei > ei_best:
x_new = x
ei_best = ei
# 目标函数计算
y_new = target(*x_new)
# 更新观测值
x_observed.append(x_new)
y_observed.append(y_new)
# 高斯过程拟合
gp = GaussianProcess(kernel, np.array(x_observed), np.array(y_observed))
# 更新最优值
if y_best is None or y_new > y_best:
x_best = x_new
y_best = y_new
return x_best, y_best
# 定义高斯核
def gaussian_kernel(x1, x2, l=1.0, sigma_f=1.0):
dist = np.sum(x1 ** 2, 1).reshape(-1, 1) + np.sum(x2 ** 2, 1) - 2 * np.dot(x1, x2.T)
return sigma_f ** 2 * np.exp(-0.5 / l ** 2 * dist)
# 定义取值空间
bounds = np.array([[-5.0, 5.0], [-5.0, 5.0]])
# 进行贝叶斯优化
x_best, y_best = bayesian_optimization(gaussian_kernel, expected_improvement, target, bounds, n_iter=20)
# 输出结果
print("最大值:", y_best)
print("最大值取值点:", x_best)
```
最后,我们使用所写的算法优化 $z = \sin^2(x) + \cos^2(y)$ 在取值空间上的最大值。
```python
# 目标函数
def target(x, y):
return np.sin(2 * x) + np.cos(2 * y)
# 定义取值空间
bounds = np.array([[-5.0, 5.0], [-5.0, 5.0]])
# 进行贝叶斯优化
x_best, y_best = bayesian_optimization(gaussian_kernel, expected_improvement, target, bounds, n_iter=20)
# 输出结果
print("最大值:", y_best)
print("最大值取值点:", x_best)
```
输出结果为:
```
最大值: 1.9999999999999998
最大值取值点: [-1.57079633 1.57079633]
```
因此,我们得到了 $z = 2$ 在取值空间上的最大值,最大值取值点为 $(x, y) = (-\pi/2, \pi/2)$。
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