代码生成 python实现最大割算法的随机版和去随机版
时间: 2023-11-28 11:10:59 浏览: 18
最割问题是一种经典的组合优化问题,其目标是将无向图的顶点划分成两个集合,使得两个集合中的顶点之间的边数最小。
以下是Python实现最大割算法的随机版和去随机版的代码:
随机版:
```python
import random
def max_cut_random(graph):
n = len(graph)
x = [random.choice([0, 1]) for i in range(n)]
while True:
y = [1 - i for i in x]
cut = 0
for i in range(n):
for j in range(i+1, n):
if graph[i][j] == 1 and x[i] != x[j]:
cut += 1
for i in range(n):
diff = cut
for j in range(n):
if graph[i][j] == 1:
if x[i] != x[j]:
diff -= 1
else:
diff += 1
if diff > 0:
x[i] = 1 - x[i]
if x == y:
break
return cut
# 示例代码
graph = [[0, 1, 1, 0], [1, 0, 1, 1], [1, 1, 0, 1], [0, 1, 1, 0]]
cut = max_cut_random(graph)
print("最大割值为:", cut)
```
去随机版:
```python
def max_cut(graph):
n = len(graph)
x = [0 for i in range(n)]
for i in range(n):
if sum(graph[i]) >= n / 2:
x[i] = 1
while True:
cut = 0
for i in range(n):
for j in range(i+1, n):
if graph[i][j] == 1 and x[i] != x[j]:
cut += 1
for i in range(n):
diff = cut
for j in range(n):
if graph[i][j] == 1:
if x[i] != x[j]:
diff -= 1
else:
diff += 1
if diff > 0:
x[i] = 1 - x[i]
if diff == 0:
break
return cut
# 示例代码
graph = [[0, 1, 1, 0], [1, 0, 1, 1], [1, 1, 0, 1], [0, 1, 1, 0]]
cut = max_cut(graph)
print("最大割值为:", cut)
```
其中,`graph`是输入的无向图的邻接矩阵,返回值为最大割值。