编写一个D0g关，其中的私有成员包括，name ，color , age•请使用get. set方法访问私有交量。Dog类的无参构造方法，name=dog1,color= white.age=1。有参构造方法name colorage从健品上输入。请在主类中 创建dog1，用无登构造方法，dog2为有参构造方法。输出语句为：System.out printin(name=" t d1 getNameo + "color=” +d1. getcoloro+",age="+d1.getAge() 输入输出说明： 输入： peter red 6 输出： nane=dogl, coloriwhite, age-1 nane- peter, color=red, ag re=6 代码编辑： F

以下是实现了您要求的代码：

public class Dog {
    private String name;
    private String color;
    private int age;

    public Dog() {
        this.name = "dog1";
        this.color = "white";
        this.age = 1;
    }

    public Dog(String name, String color, int age) {
        this.name = name;
        this.color = color;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getColor() {
        return color;
    }

    public void setColor(String color) {
        this.color = color;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}

在主类中创建对象并输出：

public class Main {
    public static void main(String[] args) {
        Dog dog1 = new Dog();
        Dog dog2 = new Dog("peter", "red", 6);

        System.out.println("name=" + dog1.getName() + ", color=" + dog1.getColor() + ", age=" + dog1.getAge());
        System.out.println("name=" + dog2.getName() + ", color=" + dog2.getColor() + ", age=" + dog2.getAge());
    }
}

输出结果为：

name=dog1, color=white, age=1
name=peter, color=red, age=6