用python编写从52张牌中随机抽取4张牌（洗牌前后取前四张）

好的，这是一个关于Python编程的问题，我可以回答。下面是一个实现这个功能的Python程序：

import random

deck = ['Ace of Spades', '2 of Spades', '3 of Spades', '4 of Spades', '5 of Spades', '6 of Spades', '7 of Spades', '8 of Spades', '9 of Spades', '10 of Spades', 'Jack of Spades', 'Queen of Spades', 'King of Spades', 'Ace of Hearts', '2 of Hearts', '3 of Hearts', '4 of Hearts', '5 of Hearts', '6 of Hearts', '7 of Hearts', '8 of Hearts', '9 of Hearts', '10 of Hearts', 'Jack of Hearts', 'Queen of Hearts', 'King of Hearts', 'Ace of Diamonds', '2 of Diamonds', '3 of Diamonds', '4 of Diamonds', '5 of Diamonds', '6 of Diamonds', '7 of Diamonds', '8 of Diamonds', '9 of Diamonds', '10 of Diamonds', 'Jack of Diamonds', 'Queen of Diamonds', 'King of Diamonds', 'Ace of Clubs', '2 of Clubs', '3 of Clubs', '4 of Clubs', '5 of Clubs', '6 of Clubs', '7 of Clubs', '8 of Clubs', '9 of Clubs', '10 of Clubs', 'Jack of Clubs', 'Queen of Clubs', 'King of Clubs']

random.shuffle(deck)

hand = deck[:4]

print(hand)

在这个程序中，我们首先定义了一个包含52张牌的字符串列表，然后使用Python的random模块中的shuffle函数将牌洗混。接着，我们通过列表分片操作deck[:4]从洗好的牌堆中取出前4张牌，存储到变量hand中，并打印输出。

运行程序后，就可以获得随机抽取的4张牌的结果了。