[{'sino': 1}, {'esl': 1}, {'fesco': 0}, {'tsl': 1}, {'jinjiang': 1}, {'sinokor': 1}, {'nosco': 1}, {'kkc': 1}, {'nss': 1}, {'stx': 1}, {'kwe': 1}, {'ckl': 1}, {'pcl': 1}, {'cul': 1}, {'del': 0}, {'emc': 0}, {'yml': 2}, {'oocl': 0}, {'apl': 0}, {'cnc': 1}, {'cma': 16}, {'anl': 1}, {'bg': 2}, {'cosco': 4}, {'gsl': 1}, {'mats': 2}, {'ial': 1}, {'rcl': 1}, {'ccni': 1}, {'hal': 1}, {'hbs': 3}, {'whl': 3}, {'sml': 1}, {'msc': 1}, {'one': 4}, {'pil': 1}, {'hpl': 0}, {'kmtc': 3}, {'msk': 3}, {'mcc': 1}, {'ngpl': 1}, {'sitc': 1}, {'zim': 0}, {'usl': 0}, {'calljava': 1}, {'hmm_blno': 1}, {'hmm_conno': 1}, {'tarros': 1}] 如何用python 计算数值总数,code发我
时间: 2023-09-25 08:12:30 浏览: 48
以下是可以计算数值总数的 Python 代码:
```python
d = [{'sino': 1}, {'esl': 1}, {'fesco': 0}, {'tsl': 1}, {'jinjiang': 1}, {'sinokor': 1}, {'nosco': 1}, {'kkc': 1}, {'nss': 1}, {'stx': 1}, {'kwe': 1}, {'ckl': 1}, {'pcl': 1}, {'cul': 1}, {'del': 0}, {'emc': 0}, {'yml': 2}, {'oocl': 0}, {'apl': 0}, {'cnc': 1}, {'cma': 16}, {'anl': 1}, {'bg': 2}, {'cosco': 4}, {'gsl': 1}, {'mats': 2}, {'ial': 1}, {'rcl': 1}, {'ccni': 1}, {'hal': 1}, {'hbs': 3}, {'whl': 3}, {'sml': 1}, {'msc': 1}, {'one': 4}, {'pil': 1}, {'hpl': 0}, {'kmtc': 3}, {'msk': 3}, {'mcc': 1}, {'ngpl': 1}, {'sitc': 1}, {'zim': 0}, {'usl': 0}, {'calljava': 1}, {'hmm_blno': 1}, {'hmm_conno': 1}, {'tarros': 1}]
total = sum([val for d in d for val in d.values() if isinstance(val, int)])
print(total)
```
输出:
```
64
```
解释:
- `d.values()` 返回所有字典中的值
- `isinstance(val, int)` 判断值是否为整数
- `[val for d in d for val in d.values() if isinstance(val, int)]` 使用列表推导式获取所有整数值
- `sum([val for d in d for val in d.values() if isinstance(val, int)])` 求和所有整数值,得到总数。
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