用MIPS汇编实现输出2022年日历
时间: 2023-11-22 22:55:44 浏览: 32
以下是用MIPS汇编实现输出2022年日历的代码:
```
.data
monthNames: .asciiz "JanFebMarAprMayJunJulAugSepOctNovDec"
dayNames: .asciiz "SuMoTuWeThFrSa"
year: .word 2022
monthDays: .word 31,28,31,30,31,30,31,31,30,31,30,31
leapMonthDays: .word 31,29,31,30,31,30,31,31,30,31,30,31
newline: .asciiz "\n"
space: .asciiz " "
.text
main:
# Print year
la $a0, year
lw $a0, ($a0)
li $v0, 1
syscall
la $a0, newline
li $v0, 4
syscall
# Check if it's a leap year
li $t0, 0
lw $t1, year
li $t2, 4
div $t1, $t2
mfhi $t3
beq $t3, $zero, leapYear
# Not a leap year
la $t4, monthDays
# Print each month
li $t5, 0 # month counter
li $t6, 1 # day counter
li $t7, 1 # weekday counter
li $t8, 12 # number of months
loop:
# Print month name
la $t9, monthNames
add $t9, $t9, $t5
lb $a0, ($t9)
li $v0, 11
syscall
la $a0, space
li $v0, 4
syscall
# Print year and newline
lw $a0, year
li $v0, 1
syscall
la $a0, newline
li $v0, 4
syscall
# Print day names
la $a0, dayNames
li $v0, 4
syscall
la $a0, newline
li $v0, 4
syscall
# Print days of the month
lw $t0, ($t4) # get number of days in month
loop2:
# Print spaces until first day of month
beq $t6, 2, printDay
sub $t6, $t6, 1
la $a0, space
li $v0, 4
syscall
b loop2
printDay:
# Print day
move $a0, $t6
li $v0, 1
syscall
# Increment weekday counter
addi $t7, $t7, 1
# Check if end of week
beq $t7, 8, endOfWeek
# Print space
la $a0, space
li $v0, 4
syscall
# Increment day counter
addi $t6, $t6, 1
# Check if end of month
beq $t6, $t0, endOfMonth
# Continue printing days of month
j printDay
endOfWeek:
# Print newline
la $a0, newline
li $v0, 4
syscall
# Reset weekday counter
li $t7, 1
# Increment day counter
addi $t6, $t6, 1
# Check if end of month
beq $t6, $t0, endOfMonth
# Continue printing days of month
j printDay
endOfMonth:
# Print newline
la $a0, newline
li $v0, 4
syscall
# Increment month counter
addi $t5, $t5, 1
# Check if end of year
beq $t5, $t8, endOfYear
# Check if next month is February and it's a leap year
bne $t5, 1, notFeb
b leapYear
notFeb:
# Not February or not a leap year
addi $t4, $t4, 4 # move to next month
li $t6, 1 # reset day counter
j loop
endOfYear:
# Exit program
li $v0, 10
syscall
leapYear:
# Leap year
la $t4, leapMonthDays
# Print each month
li $t5, 0 # month counter
li $t6, 1 # day counter
li $t7, 1 # weekday counter
li $t8, 12 # number of months
loop3:
# Print month name
la $t9, monthNames
add $t9, $t9, $t5
lb $a0, ($t9)
li $v0, 11
syscall
la $a0, space
li $v0, 4
syscall
# Print year and newline
lw $a0, year
li $v0, 1
syscall
la $a0, newline
li $v0, 4
syscall
# Print day names
la $a0, dayNames
li $v0, 4
syscall
la $a0, newline
li $v0, 4
syscall
# Print days of the month
lw $t0, ($t4) # get number of days in month
loop4:
# Print spaces until first day of month
beq $t6, 2, printLeapDay
sub $t6, $t6, 1
la $a0, space
li $v0, 4
syscall
b loop4
printLeapDay:
# Print day
move $a0, $t6
li $v0, 1
syscall
# Increment weekday counter
addi $t7, $t7, 1
# Check if end of week
beq $t7, 8, leapEndOfWeek
# Print space
la $a0, space
li $v0, 4
syscall
# Increment day counter
addi $t6, $t6, 1
# Check if end of month
beq $t6, $t0, leapEndOfMonth
# Continue printing days of month
j printLeapDay
leapEndOfWeek:
# Print newline
la $a0, newline
li $v0, 4
syscall
# Reset weekday counter
li $t7, 1
# Increment day counter
addi $t6, $t6, 1
# Check if end of month
beq $t6, $t0, leapEndOfMonth
# Continue printing days of month
j printLeapDay
leapEndOfMonth:
# Print newline
la $a0, newline
li $v0, 4
syscall
# Increment month counter
addi $t5, $t5, 1
# Check if end of year
beq $t5, $t8, endOfYear
# Check if next month is February and it's not a leap year
bne $t5, 1, notLeapFeb
# February but not a leap year, move to next month
addi $t4, $t4, 4
li $t6, 1
j loop3
notLeapFeb:
# Not February or a leap year
addi $t4, $t4, 4 # move to next month
li $t6, 1 # reset day counter
j loop3
```
请注意,该代码可能不是最优解决方案,并且可能需要进行额外的测试和调整才能确保正确性。