In this correspondence we derive a STSA estimator which minimizes the mean-square error of the log-spectra (i.e., the original STSA and its estimator) and examine it in enhancing noisy speech. -We found that this estimator is superior to the MMSE STSA estimator derived in [ 11 since it results in a much lower residual noise level without further affecting the speech itself. In fact, the new estimator results in a very similar enhanced speech quality as that obtained with the MMSE STSA estimator of [ 11, which takes into account the signal presence uncertainty.翻译成中文

在这篇文章中，我们推导出一种最小化对数谱的均方误差的STSA估计器，并在增强嘈杂语音方面进行了研究。我们发现，这个估计器比[11]中导出的MMSE STSA估计器更优秀，因为它在不进一步影响语音本身的情况下，能够得到更低的残余噪声水平。事实上，这个新的估计器得到的增强语音质量与[11]中考虑到信号存在不确定性的MMSE STSA估计器非常相似。

相关问题

(Telephone Number Word Generator) Standard telephone keypads contain the digits 0 through 9. The numbers 2 through 9 each have three letters associated with them, as is indicated by the following table: Many people find it difficult to memorize phone numbers, so they use the correspondence between digits and letters to develop seven-letter words that correspond to their phone numbers. For example, a person whose telephone number is 686-2377 might use the correspondence indi- cated in the above table to develop the seven-letter word “NUMBERS.” Businesses frequently attempt to get telephone numbers that are easy for their clients to remember. If a business can advertise a simple word for its customers to dial, then no doubt the business will receive a few more calls. Each seven-letter word corresponds to exactly one seven-digit telephone number. The restaurant wishing to increase its take-home business could surely do so with the number 825-3688 (i.e., “TAKEOUT”). Each seven-digit phone number corresponds to many separate seven-letter words. Unfortunately, most of these represent unrecognizable juxtaposi- tions of letters. It’s possible, however, that the owner of a barber shop would be pleased to know that the shop’s telephone number, 424-7288, corresponds to “HAIRCUT.” A veterinarian with the phone number 738-2273 would be happy to know that the number corresponds to “PETCARE.” Write a C++ program that, given a seven-digit number, writes to a file every possible seven-letter word corresponding to that number. There are 2187 (3 to the seventh power) such words. Avoid phone numbers with the digits 0 and 1.

Sure, I can help you with that! Here's the C++ code to generate all possible seven-letter words for a given seven-digit phone number:

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

// Function to generate all possible seven-letter words for a given phone number
void generateWords(string number, string word, int index, ofstream& outfile) {
    // Base case: all digits have been processed
    if (index == number.size()) {
        outfile << word << endl;  // write the word to the output file
        return;
    }

    // Generate all possible letters for the current digit
    string letters = "";
    switch (number[index]) {
        case '2':
            letters = "ABC";
            break;
        case '3':
            letters = "DEF";
            break;
        case '4':
            letters = "GHI";
            break;
        case '5':
            letters = "JKL";
            break;
        case '6':
            letters = "MNO";
            break;
        case '7':
            letters = "PQRS";
            break;
        case '8':
            letters = "TUV";
            break;
        case '9':
            letters = "WXYZ";
            break;
    }

    // Recursively generate words for the remaining digits
    for (int i = 0; i < letters.size(); i++) {
        generateWords(number, word + letters[i], index + 1, outfile);
    }
}

int main() {
    string number;
    cout << "Enter a seven-digit phone number (no 0's or 1's): ";
    cin >> number;

    // Open an output file to write the generated words
    ofstream outfile("words.txt");

    // Generate all possible seven-letter words
    generateWords(number, "", 0, outfile);

    // Close the output file
    outfile.close();

    cout << "Done! Check the output file 'words.txt' for the generated words." << endl;
    return 0;
}

To use this program, simply run it in a C++ compiler and enter a seven-digit phone number (without any 0's or 1's) when prompted. The program will generate all possible seven-letter words corresponding to that phone number and write them to a file called "words.txt".

链接：https://ac.nowcoder.com/acm/contest/59935/B 来源：牛客网 It's New Year's Day, and it was a tradition for ancient Chinese to write couplets. Sometimes one person would give the first line, and another person would need to come up with the second line based on the sentence structure and meaning, which requires considerable literary skills. Now given a first line of length nn, with each character represented by a number for convenience, you need to write a second line that meets the following requirements: 1. Each number in the second line must be a positive integer. 2. Each number in the second line must not appear in the first line. 3. The ii-th number in the first line corresponds to the ii-th number in the second line. You can specify the correspondence relationship arbitrarily, but the relationship must be consistent and unique. For example, if you specify that the number 3 in the first line corresponds to the number 1 in the second line, then another non-3 number in the first line cannot correspond to the number 1, and all 3s in the first line must correspond to 1.用c++给我把这道题做出来

好的，这道题目可以使用一个桶来记录第一行中出现的数字，然后从1到n遍历，如果该数字没有在桶中出现过，则将其加入到第二行中，并在桶中标记该数字已经出现过。具体实现可以参考以下代码：

#include <iostream>
#include <vector>
using namespace std;

int main() {
    int n;
    cin >> n;
    vector<int> first(n);
    vector<bool> used(n + 1, false);
    for (int i = 0; i < n; i++) {
        cin >> first[i];
        used[first[i]] = true; // 记录第一行中出现的数字
    }
    vector<int> second(n);
    for (int i = 1; i <= n; i++) {
        if (!used[i]) {
            second[first[i - 1] - 1] = i; // 根据题目要求，第i个数字对应第i个位置
        }
    }
    for (int i = 0; i < n; i++) {
        cout << second[i] << " ";
    }
    cout << endl;
    return 0;
}

希望能帮到你！