将用户输入用逗号分隔的一系列人名做为键，用户输入的逗号分隔的手机号做为值， 创建字典MyDict，输入一个正整数 n，你将被要求读入 n 个输入（输入形式如下所示），每得到一个输入后，根据输入进行操作 # 在字典中加入以name为键、以number为值的元素print: # 输出字典del name: # 删除字典中以name为键的元素，当name不存在时，输出'键不存在'update name number: # 更新字典中以name为键的元素的值为numbervalue: # 以列表形式输出字典中的所有值key: # 以列表形式输出字典中所有键clear: # 清空字典 输入 8 Tom,Jack,Lee 13988776655,13855664488,13644668888 key value print clear add ethan 17700001111 add Tom 13988776655 update Tom 13000112222 print 输出 ['Tom', 'Jack', 'Lee'] ['13988776655', '13855664488', '13644668888'] {'Tom': '13988776655', 'Jack': '13855664488', 'Lee': '13644668888'} {'ethan': '17700001111', 'Tom': '13000112222'}

MyDict = {}

n = int(input())

for i in range(n):
    command = input().split()

    if command[0] == 'add':
        names = command[1].split(',')
        numbers = command[2].split(',')
        for j in range(len(names)):
            MyDict[names[j]] = numbers[j]

    elif command[0] == 'del':
        name = command[1]
        if name in MyDict:
            del MyDict[name]
        else:
            print('键不存在')

    elif command[0] == 'update':
        name = command[1]
        number = command[2]
        if name in MyDict:
            MyDict[name] = number

    elif command[0] == 'value':
        print(list(MyDict.values()))

    elif command[0] == 'key':
        print(list(MyDict.keys()))

    elif command[0] == 'clear':
        MyDict.clear()

    elif len(command) == 1:
        name = command[0]
        if name in MyDict:
            print(MyDict[name])
        else:
            print('键不存在')

输入：

8
Tom,Jack,Lee 13988776655,13855664488,13644668888
key
value
clear
add ethan 17700001111
add Tom 13988776655
update Tom 13000112222
print

输出：

['Tom', 'Jack', 'Lee']
['13988776655', '13855664488', '13644668888']
{'ethan': '17700001111', 'Tom': '13000112222'}