编写一段程序,编程计算, sn=(1-1/2)+(1/3-1/4)+...+(1/(2n-1)-1/(2n)),结果保留两位小数
时间: 2023-10-26 14:06:20 浏览: 68
Sure, I can help you with that! Here's the code in Python:
```
n = int(input("Enter the value of n: "))
sn = 1
for i in range(2, 2*n+1, 2):
sn *= ((i-1)/i)
print("The result of the calculation is:", "{:.2f}".format(sn))
```
You can copy and paste this code into your preferred Python environment and run it to get the result. Let me know if you need any further assistance!
相关问题
python编写程序计算sn=1+1/2+1/3....+1/n
以下是两种Python编写程序计算sn=1+1/2+1/3....+1/n的方法:
方法一:使用循环累加
```python
def calc_sn(n):
s = 0
for i in range(1, n+1):
s += 1/i
return s
if __name__ == '__main__':
n = int(input("请输入n的值:"))
sn = calc_sn(n)
print("sn的值为:", sn)
```
方法二:使用递归
```python
def calc_sn(n):
if n == 1:
return 1
else:
return 1/n + calc_sn(n-1)
if __name__ == '__main__':
n = int(input("请输入n的值:"))
sn = calc_sn(n)
print("sn的值为:", sn)
```
编写程序,计算Sn=1+1/2+1/3+…
编写程序sy4-1.c,输入n,计算并输出如下多项式的值:Sn=1 1/2! 1/3! 1/4! … 1/n!。以下是一个示例程序,你可以根据自己的需求进行修改和调试:
#include <stdio.h>
int main() {
int n;
double Sn = 0.0, factorial = 1.0;
printf("请输入n的值:");
scanf("%d", &n);
for (int i = 1; i <= n; i++) {
factorial *= i;
Sn += 1 / factorial;
}
printf("Sn的值为:%f\n", Sn);
return 0;
}