编写一段程序，编程计算， sn=(1-1/2)+(1/3-1/4)+...+(1/(2n-1)-1/(2n))，结果保留两位小数

Sure, I can help you with that! Here's the code in Python:

n = int(input("Enter the value of n: ")) 
sn = 1 
for i in range(2, 2*n+1, 2): 
    sn *= ((i-1)/i) 
print("The result of the calculation is:", "{:.2f}".format(sn))

You can copy and paste this code into your preferred Python environment and run it to get the result. Let me know if you need any further assistance!