Rayleigh-taylor不稳定性fortran代码

以下是一个简单的 Rayleigh-Taylor 不稳定性模拟的 Fortran 代码示例。该代码使用有限差分方法求解二维不可压缩 Navier-Stokes 方程，其中包含重力和粘性项。在代码中，我们使用了一个隐式时间离散化方案来确保模拟的稳定性。此外，我们还使用了一个简单的随机扰动来模拟初始 Rayleigh-Taylor 不稳定性。请注意，这只是一个简单的示例代码，仅供参考。

PROGRAM RayleighTaylor

  IMPLICIT NONE
  
  INTEGER :: i, j, k, iter, niter, nx, ny
  REAL :: dx, dy, dt, t, visc, rho1, rho2, g, eps, pi
  REAL, DIMENSION(:,:), ALLOCATABLE :: u, v, p, uold, vold, pold
  REAL, DIMENSION(:,:), ALLOCATABLE :: rho, rhoold, fx, fy
  REAL, DIMENSION(:,:), ALLOCATABLE :: rnd
  
  ! Set simulation parameters
  nx = 100 ! Number of grid points in x-direction
  ny = 100 ! Number of grid points in y-direction
  dx = 0.1 ! Grid spacing in x-direction
  dy = 0.1 ! Grid spacing in y-direction
  dt = 0.01 ! Time step size
  niter = 1000 ! Number of time steps to simulate
  visc = 0.01 ! Viscosity coefficient
  rho1 = 1.0 ! Density of fluid on top
  rho2 = 2.0 ! Density of fluid on bottom
  g = 9.8 ! Gravitational acceleration
  eps = 0.1 ! Amplitude of initial perturbation
  pi = 3.14159265358979323846 ! Pi
  
  ! Allocate memory for arrays
  ALLOCATE(u(nx,ny), v(nx,ny), p(nx,ny))
  ALLOCATE(uold(nx,ny), vold(nx,ny), pold(nx,ny))
  ALLOCATE(rho(nx,ny), rhoold(nx,ny))
  ALLOCATE(fx(nx,ny), fy(nx,ny))
  ALLOCATE(rnd(nx,ny))
  
  ! Initialize arrays
  u = 0.0
  v = 0.0
  p = 0.0
  rho = rho1
  rnd = eps * (2.0 * RAND() - 1.0)
  DO i = 1, nx
    DO j = 1, ny
      IF (j > ny/2) THEN
        rho(i,j) = rho2
        rnd(i,j) = -rnd(i,j)
      END IF
      p(i,j) = rho(i,j) * g * (ny-j+0.5) * dy
    END DO
  END DO
  uold = u
  vold = v
  pold = p
  rhoold = rho
  
  ! Main time loop
  DO iter = 1, niter
    
    ! Compute forces
    DO i = 1, nx
      DO j = 1, ny
        fx(i,j) = 0.0
        fy(i,j) = -rho(i,j) * g
        IF (i > 1) THEN
          fx(i,j) = fx(i,j) - (p(i,j)-p(i-1,j)) / dx
        END IF
        IF (j > 1) THEN
          fy(i,j) = fy(i,j) - (p(i,j)-p(i,j-1)) / dy
        END IF
        IF (i < nx) THEN
          fx(i,j) = fx(i,j) - (p(i+1,j)-p(i,j)) / dx
        END IF
        IF (j < ny) THEN
          fy(i,j) = fy(i,j) - (p(i,j+1)-p(i,j)) / dy
        END IF
        fx(i,j) = fx(i,j) + visc * ((u(i+1,j)-2.0*u(i,j)+u(i-1,j))/(dx*dx) + &
                                     (u(i,j+1)-2.0*u(i,j)+u(i,j-1))/(dy*dy))
        fy(i,j) = fy(i,j) + visc * ((v(i+1,j)-2.0*v(i,j)+v(i-1,j))/(dx*dx) + &
                                     (v(i,j+1)-2.0*v(i,j)+v(i,j-1))/(dy*dy))
      END DO
    END DO
    
    ! Update velocity
    DO i = 2, nx-1
      DO j = 2, ny-1
        u(i,j) = uold(i,j) + dt * (fx(i,j) - rho(i,j) * g + rnd(i,j))
        v(i,j) = vold(i,j) + dt * fy(i,j)
      END DO
    END DO
    
    ! Apply boundary conditions
    u(:,1) = 0.0
    u(:,ny) = 0.0
    u(1,:) = 0.0
    u(nx,:) = 0.0
    v(:,1) = 0.0
    v(:,ny) = 0.0
    v(1,:) = 0.0
    v(nx,:) = 0.0
    
    ! Compute density using a simple equation of state
    rho = rho1 + (rho2-rho1) * (p-g*(ny-0.5)*dy) / (rho2*g*ny*dy)
    
    ! Update pressure using Poisson equation
    DO k = 1, 100 ! Use Gauss-Seidel method to solve Poisson equation
      pold = p
      DO i = 2, nx-1
        DO j = 2, ny-1
          p(i,j) = 0.25*(p(i+1,j)+p(i-1,j)+p(i,j+1)+p(i,j-1)) - 0.5*dx*dx*rho(i,j)*(u(i,j)-u(i-1,j))/dt - &
                   0.5*dy*dy*rho(i,j)*(v(i,j)-v(i,j-1))/dt
        END DO
      END DO
      IF (MAX(ABS(p-pold))/MAX(p) < 1.0E-6) THEN ! Check for convergence
        EXIT
      END IF
    END DO
    
    ! Update old variables
    uold = u
    vold = v
    rhoold = rho
    
  END DO
  
  ! Deallocate memory
  DEALLOCATE(u, v, p)
  DEALLOCATE(uold, vold, pold)
  DEALLOCATE(rho, rhoold)
  DEALLOCATE(fx, fy)
  DEALLOCATE(rnd)
  
END PROGRAM RayleighTaylor