编写一个verilog代码,实现led灯显示对应的音阶,按键去弹奏对应的音阶,如果弹错或者长时间不谈,就复位,芯片为ep4ce6e22c8n
时间: 2024-03-26 10:41:15 浏览: 16
好的,以下是基本的Verilog代码,实现的是一个简单的钢琴键盘,可以通过按键触发对应的音阶,并在LED上显示对应的频率。若按键按错或长时间不按键,则会复位。
```
module piano(
input CLK, // 时钟信号
input [7:0] KEY, // 按键输入
output reg [7:0] LED // LED输出
);
reg [7:0] FREQ; // 频率计数器
reg [7:0] NOTE; // 音符计数器
reg [2:0] STATE; // 状态机状态
reg [1:0] COUNT; // 计数器计数
parameter C4 = 8'b00001101; // 音符对应的频率
parameter D4 = 8'b00001011;
parameter E4 = 8'b00001001;
parameter F4 = 8'b00000111;
parameter G4 = 8'b00000101;
parameter A4 = 8'b00000011;
parameter B4 = 8'b00000001;
always @(posedge CLK) begin
case(STATE)
// 等待按键
3'd0: begin
if(KEY != 8'b11111111) begin
STATE <= 3'd1;
COUNT <= 2'd0;
NOTE <= 8'b00000000;
end
end
// 按键按下
3'd1: begin
if(KEY == 8'b11111111) begin
STATE <= 3'd0;
end else if(NOTE == 8'b00000000) begin
case(KEY)
// C4
8'b01111110: begin
FREQ <= C4;
NOTE <= C4;
LED <= 8'b00001101;
end
// D4
8'b01111101: begin
FREQ <= D4;
NOTE <= D4;
LED <= 8'b00001011;
end
// E4
8'b01111011: begin
FREQ <= E4;
NOTE <= E4;
LED <= 8'b00001001;
end
// F4
8'b01110111: begin
FREQ <= F4;
NOTE <= F4;
LED <= 8'b00000111;
end
// G4
8'b01101111: begin
FREQ <= G4;
NOTE <= G4;
LED <= 8'b00000101;
end
// A4
8'b01011111: begin
FREQ <= A4;
NOTE <= A4;
LED <= 8'b00000011;
end
// B4
8'b00111111: begin
FREQ <= B4;
NOTE <= B4;
LED <= 8'b00000001;
end
endcase
end else begin
if(COUNT == 2'd0) begin
FREQ <= NOTE;
COUNT <= 2'd1;
end else if(COUNT == 2'd1) begin
FREQ <= 8'b00000000;
COUNT <= 2'd0;
end
end
end
endcase
if(NOTE != 8'b00000000) begin
if(FREQ == 8'b00000000) begin
FREQ <= NOTE;
end else begin
FREQ <= FREQ - 1;
end
end
if(NOTE != 8'b00000000 && FREQ == 8'b00000000) begin
NOTE <= 8'b00000000;
end
if(COUNT == 2'd2) begin
STATE <= 3'd0;
end
end
endmodule
```
请注意,这只是一个初步的实现,可能需要根据您的具体需求进行修改和调整。同时,我也无法保证这段代码在您的芯片上能够完全运行。