syms x y; f = exp(7-sin(x))*y; g = y^2 - 1; h = @(x,y) -f; [x0, y0] = vpasolve([gradient(f,x)==0, gradient(f,y)==0, g==0], [x,y], [-100, -100, -100], [100, 100, 100]); max_val = h(x0, y0); disp(max_val);
时间: 2023-05-24 08:04:23 浏览: 59
matlab在数值分析中的应用-Runge-kuttaPPT.ppt
There seems to be an error in the code. One possible correction is:
syms x y;
f = exp(7-sin(x))*y;
g = y^2 - 1;
h = @(x,y) -f;
[x0, y0] = vpasolve([gradient(f,x)==0, gradient(f,y)==0, g==0], [x,y], [-100, -100], [100, 100]);
max_val = h(x0, y0);
disp(max_val);
This code finds the maximum value of -f (which is equivalent to finding the minimum value of f) subject to the constraint g=0. The syntax "vpasolve" is used to solve the system of equations obtained by setting the gradients of f equal to zero and the constraint g=0. The solution (x0,y0) is then used to evaluate -f at the maximum point. The result is displayed using "disp".
阅读全文