用C++实现请根据输入的数据创建一棵二叉排序树。然后执行相应操作。 1 删除某一值为x的结点 2 求指定结点y在二叉排序树中的层数

好的，我可以为您提供相关的C++代码。请注意，这里的代码是基于命令行输入，您可以在代码中根据需要进行修改。

#include<iostream>

using namespace std;

// 定义树结点
struct TreeNode {
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};

// 插入新结点
TreeNode* insert(TreeNode* root, int val) {
    if (root == NULL) {
        return new TreeNode(val);
    }
    if (val < root->val) {
        root->left = insert(root->left, val);
    }
    else {
        root->right = insert(root->right, val);
    }
    return root;
}

// 删除指定结点
TreeNode* deleteNode(TreeNode* root, int val) {
    if (root == NULL) {
        return NULL;
    }
    if (val < root->val) {
        root->left = deleteNode(root->left, val);
    }
    else if (val > root->val) {
        root->right = deleteNode(root->right, val);
    }
    else {
        if (root->left == NULL) {
            return root->right;
        }
        else if (root->right == NULL) {
            return root->left;
        }
        TreeNode* minNode = root->right;
        while (minNode->left != NULL) {
            minNode = minNode->left;
        }
        root->val = minNode->val;
        root->right = deleteNode(root->right, minNode->val);
    }
    return root;
}

// 查找指定结点的层数
int findLevel(TreeNode* root, int val) {
    if (root == NULL) {
        return -1;
    }
    if (root->val == val) {
        return 0;
    }
    if (val < root->val) {
        int level = findLevel(root->left, val);
        if (level == -1) {
            return -1;
        }
        else {
            return level + 1;
        }
    }
    else {
        int level = findLevel(root->right, val);
        if (level == -1) {
            return -1;
        }
        else {
            return level + 1;
        }
    }
}

int main() {
    TreeNode* root = NULL;

    // 输入数据，构建二叉排序树
    int n;
    cin >> n;
    for (int i = 0; i < n; i++) {
        int val;
        cin >> val;
        root = insert(root, val);
    }

    // 删除指定结点
    int x;
    cin >> x;
    root = deleteNode(root, x);

    // 查找指定结点的层数
    int y;
    cin >> y;
    int level = findLevel(root, y);
    if (level == -1) {
        cout << "Node " << y << " not found in the tree." << endl;
    }
    else {
        cout << "Node " << y << " is at level " << level << " in the tree." << endl;
    }

    return 0;
}

希望这段代码能够帮助您实现所需的功能。