用c语言编写哈夫曼树解码的代码并在main函数中实现输出解码后的结果

好的，以下是用C语言编写哈夫曼树解码的代码，并在main函数中实现输出解码后的结果的示例：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_TREE_NODE 1000

// 哈夫曼树节点结构体
typedef struct huffman_node {
    char data;
    int weight;
    int parent;
    int left_child;
    int right_child;
} HuffmanNode;

// 哈夫曼树结构体
typedef struct huffman_tree {
    HuffmanNode nodes[MAX_TREE_NODE];
    int node_count;
} HuffmanTree;

// 构建哈夫曼树
void build_huffman_tree(HuffmanTree* tree, char* data, int* weights, int count) {
    // 初始化节点
    for (int i = 0; i < count; i++) {
        tree->nodes[i].data = data[i];
        tree->nodes[i].weight = weights[i];
        tree->nodes[i].parent = -1;
        tree->nodes[i].left_child = -1;
        tree->nodes[i].right_child = -1;
    }
    tree->node_count = count;

    // 构建哈夫曼树
    for (int i = count; i < MAX_TREE_NODE; i++) {
        tree->nodes[i].data = '\0';
        tree->nodes[i].weight = 0;
        tree->nodes[i].parent = -1;
        tree->nodes[i].left_child = -1;
        tree->nodes[i].right_child = -1;
    }

    for (int i = count; i < 2 * count - 1; i++) {
        int left_child = -1;
        int right_child = -1;
        int min_weight = INT_MAX;
        for (int j = 0; j < i; j++) {
            if (tree->nodes[j].parent == -1) {
                if (tree->nodes[j].weight < min_weight) {
                    right_child = left_child;
                    left_child = j;
                    min_weight = tree->nodes[j].weight;
                }
                else if (tree->nodes[j].weight == min_weight) {
                    right_child = j;
                }
            }
        }
        tree->nodes[left_child].parent = i;
        tree->nodes[right_child].parent = i;
        tree->nodes[i].left_child = left_child;
        tree->nodes[i].right_child = right_child;
        tree->nodes[i].weight = tree->nodes[left_child].weight + tree->nodes[right_child].weight;
    }
}

// 哈夫曼树解码
void huffman_decode(HuffmanTree* tree, char* encoded_data, char* decoded_data) {
    int i = 0;
    int j = 0;
    int current_node = 2 * tree->node_count - 2;
    while (encoded_data[i] != '\0') {
        if (encoded_data[i] == '0') {
            current_node = tree->nodes[current_node].left_child;
        }
        else if (encoded_data[i] == '1') {
            current_node = tree->nodes[current_node].right_child;
        }
        if (tree->nodes[current_node].left_child == -1 && tree->nodes[current_node].right_child == -1) {
            decoded_data[j] = tree->nodes[current_node].data;
            j++;
            current_node = 2 * tree->node_count - 2;
        }
        i++;
    }
    decoded_data[j] = '\0';
}

int main() {
    // 假设编码为："0010101111011110101"
    char encoded_data[] = "0010101111011110101";

    // 假设字符和权重分别为：{'a', 'b', 'c', 'd', 'e'} 和 {5, 7, 2, 8, 4}
    char data[] = {'a', 'b', 'c', 'd', 'e'};
    int weights[] = {5, 7, 2, 8, 4};
    int count = sizeof(data) / sizeof(data[0]);

    // 构建哈夫曼树
    HuffmanTree tree;
    build_huffman_tree(&tree, data, weights, count);

    // 解码
    char decoded_data[MAX_TREE_NODE];
    memset(decoded_data, 0, sizeof(decoded_data));
    huffman_decode(&tree, encoded_data, decoded_data);

    // 输出解码后的结果
    printf("Decoded data: %s\n", decoded_data);

    return 0;
}

在上述示例中，我们假设编码为："0010101111011110101"，字符和权重分别为：{'a', 'b', 'c', 'd', 'e'} 和 {5, 7, 2, 8, 4}，然后构建哈夫曼树并解码，最后输出解码后的结果。