python求10个坐标相互之间的距离并求出从第一个坐标开始经过其他几个坐标最后到达最后一个问题坐标的最短路线import math # 假设有8个坐标分别为 (x1, y1), (x2, y2), (x3, y3), (x4, y4), (x5, y5), (x6, y6), (x7, y7), (x8, y8) coordinates = [(x1, y1), (x2, y2), (x3, y3), (x4, y4), (x5, y5), (x6, y6), (x7, y7), (x8, y8)] #

下面是完整代码，包括计算距离和求解最短路径：

import math 

# 假设有10个坐标分别为 (x1, y1), (x2, y2), ..., (x10, y10)
coordinates = [(x1, y1), (x2, y2), (x3, y3), (x4, y4), (x5, y5), (x6, y6), (x7, y7), (x8, y8), (x9, y9), (x10, y10)]

# 定义一个函数计算两个坐标之间的距离 
def distance(x1, y1, x2, y2): 
    return math.sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2) 

# 初始化dp数组
dp = [[float('inf')]*10 for _ in range(8)]
dp[0][0] = 0

# 初始化path数组
path = [[0]*10 for _ in range(8)]

# 使用动态规划算法求解最短路径和路径
for i in range(1, 8):
    for j in range(1, 10):
        for k in range(j):
            dist = dp[i-1][k]+distance(coordinates[k][0], coordinates[k][1], coordinates[j][0], coordinates[j][1])
            if dist < dp[i][j]:
                dp[i][j] = dist
                path[i][j] = k

# 构造最短路径
shortest_path = [0]*8
shortest_path[0] = 0
shortest_path[-1] = 9
for i in range(7, 0, -1):
    shortest_path[i] = path[i][shortest_path[i+1]]

# 输出结果
print("每个坐标之间的距离为：")
for i in range(10):
    for j in range(i+1, 10):
        print(f"第{i+1}个坐标和第{j+1}个坐标之间的距离为：{distance(coordinates[i][0], coordinates[i][1], coordinates[j][0], coordinates[j][1])}")

print("从第一个坐标到最后一个坐标的最短路径为：", shortest_path)
print("从第一个坐标到最后一个坐标的最短路径长度为：", dp[7][9])