c++a说不和x打,c说不和x,z打,编程输出可能的对阵情况,用循环结构
时间: 2024-03-21 10:43:32 浏览: 10
以下是可能的对阵情况:
a vs. c
a vs. z
c vs. z
使用循环结构输出这些对阵情况的代码如下:
```c++
#include <iostream>
int main() {
char players[] = {'a', 'c', 'z'};
int n = sizeof(players) / sizeof(players[0]);
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
if ((players[i] == 'c' && players[j] == 'x') ||
(players[i] == 'x' && players[j] == 'c') ||
(players[i] == 'z' && players[j] == 'x') ||
(players[i] == 'x' && players[j] == 'z')) {
continue;
}
std::cout << players[i] << " vs. " << players[j] << std::endl;
}
}
return 0;
}
```
输出结果为:
```
a vs. c
a vs. z
c vs. z
```
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