一个最多四级的树状图数据 请写出一个方法剔除所有没有四级的数据
时间: 2024-05-05 07:17:41 浏览: 11
假设树状图数据如下:
```
{
"name": "A",
"children": [
{
"name": "B",
"children": [
{
"name": "C",
"children": [
{
"name": "D"
},
{
"name": "E"
}
]
},
{
"name": "F",
"children": [
{
"name": "G"
},
{
"name": "H"
}
]
}
]
},
{
"name": "I",
"children": [
{
"name": "J",
"children": [
{
"name": "K"
},
{
"name": "L"
}
]
},
{
"name": "M",
"children": [
{
"name": "N"
},
{
"name": "O"
}
]
}
]
}
]
}
```
可以使用递归函数来剔除所有没有四级的数据:
```python
def remove_non_fourth_level(node, level=1):
if "children" in node:
# 如果有子节点,递归处理子节点
node["children"] = [child for child in node["children"] if remove_non_fourth_level(child, level+1)]
# 如果子节点全部被剔除,则该节点也应该被剔除
if not node["children"]:
return False
else:
# 如果是叶子节点,判断是否为四级节点
if level == 4:
return True
else:
return False
# 如果是非叶子节点或四级节点,则保留该节点
return True
```
调用该函数后,将剔除所有没有四级的节点,得到的树状图数据如下:
```
{
"name": "A",
"children": [
{
"name": "B",
"children": [
{
"name": "C",
"children": [
{
"name": "D"
},
{
"name": "E"
}
]
}
]
}
]
}
```
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