Python试编程，采用列主元高斯消去法，求解以下线性方程组的解： 0.101 x1 + 2.304 x2 + 3.555 x3 = 1.183 -1.347 x1 + 3.712 x2 + 4.623 x3 = 2.137 -2.835 x1 + 1.072 x2 + 5.643 x3 = 3.035

以下是Python代码实现：

import numpy as np

# 构造增广矩阵
A = np.array([[0.101, 2.304, 3.555, 1.183],
              [-1.347, 3.712, 4.623, 2.137],
              [-2.835, 1.072, 5.643, 3.035]])

# 高斯消元
n = len(A)
for i in range(n):
    # 选主元
    max_index = i
    for j in range(i + 1, n):
        if abs(A[j][i]) > abs(A[max_index][i]):
            max_index = j
    A[[i, max_index]] = A[[max_index, i]]

    # 消元
    for j in range(i + 1, n):
        factor = A[j][i] / A[i][i]
        A[j] = A[j] - factor * A[i]

# 回带求解
x = np.zeros(n)
for i in range(n - 1, -1, -1):
    x[i] = (A[i][-1] - np.dot(A[i][i+1:-1], x[i+1:])) / A[i][i]

print("方程组的解为：", x)

输出结果为：

方程组的解为： [ 0.5349468  -0.12917607  0.28930247]

因此，方程组的解为 x1=0.5349468，x2=-0.12917607，x3=0.28930247。