写一段两平面相交求交线的代码
时间: 2023-03-09 19:03:31 浏览: 117
求解两平面相交的代码如下:// 计算平面相交的交线// 定义平面一
double A1, B1, C1;// 定义平面二
double A2, B2, C2;// 计算平面一的法向量
double x1 = A1;
double y1 = B1;
double z1 = C1;// 计算平面二的法向量
double x2 = A2;
double y2 = B2;
double z2 = C2;// 计算两个法向量的叉积
double x3 = y1 * z2 - z1 * y2;
double y3 = z1 * x2 - x1 * z2;
double z3 = x1 * y2 - y1 * x2;// 计算交线方程参数
double a = x3;
double b = y3;
double c = z3;
double d = -(a*A1 + b*B1 + c*C1);// 打印交线方程
printf("交线方程: %fx + %fy + %fz + %f = 0 \n", a, b, c, d);
相关问题
写一段CAD VBA代码,画出平面坐标系中的两条相交线段的角平分线,并将该角平分线旋转45°
### 回答1:
Sub DrawAngleBisector()
Dim pt1 As Variant
Dim pt2 As Variant
Dim pt3 As Variant
Dim pt4 As Variant
Dim pt5 As Variantpt1 = InputBox("请输入第一条线段点1的x坐标")
pt2 = InputBox("请输入第一条线段点1的y坐标")
pt3 = InputBox("请输入第一条线段点2的x坐标")
pt4 = InputBox("请输入第一条线段点2的y坐标")
pt5 = InputBox("请输入第二条线段点1的x坐标")'绘制第一条线段
Dim Line1 As AcadLine
Set Line1 = ThisDrawing.ModelSpace.AddLine(Array(pt1, pt2), Array(pt3, pt4))'绘制第二条线段
Dim Line2 As AcadLine
Set Line2 = ThisDrawing.ModelSpace.AddLine(Array(pt3, pt4), Array(pt5, pt6))'计算线段的中点
Dim ptMid As Variant
ptMid(0) = (pt1 + pt3) / 2
ptMid(1) = (pt2 + pt4) / 2'绘制角平分线
Dim AngleLine As AcadLine
Set AngleLine = ThisDrawing.ModelSpace.AddLine(ptMid, Array(pt5, pt6))'将角平分线移动45°
AngleLine.Rotate ptMid, 45End Sub
### 回答2:
以下是一个用CAD VBA代码绘制相交线段角平分线并将其旋转45°的例子:
在CAD中创建一个新的VBA模块,然后使用以下代码:
Sub DrawBisectorAndRotate()
Dim startPoint1 As Variant
Dim endPoint1 As Variant
Dim startPoint2 As Variant
Dim endPoint2 As Variant
'设置两个相交的线段的起点和终点坐标
startPoint1 = Array(0, 0, 0)
endPoint1 = Array(5, 0, 0)
startPoint2 = Array(2, 2, 0)
endPoint2 = Array(2, -2, 0)
'绘制两条线段
Dim line1 As AcadLine
Dim line2 As AcadLine
Set line1 = ThisDrawing.ModelSpace.AddLine(startPoint1, endPoint1)
Set line2 = ThisDrawing.ModelSpace.AddLine(startPoint2, endPoint2)
'获取相交点坐标
Dim intersectPoint As Variant
intersectPoint = line1.IntersectWith(line2, acExtendNone)
'绘制角平分线
Dim bisectorLine As AcadLine
Set bisectorLine = ThisDrawing.ModelSpace.AddLine(intersectPoint, startPoint1)
'旋转角平分线
Dim rotationAngle As Double
rotationAngle = 45 * (3.14159 / 180) '将角度转换为弧度
bisectorLine.Rotate intersectPoint, rotationAngle
End Sub
确保已经在AUTOCAD中加载了上述VBA代码,然后运行这个宏(方式视AUTOCAD版本而定)。这样,你将在AUTOCAD中获得两条相交线段的角平分线,并将其旋转45°。
### 回答3:
下面是一段基于CAD VBA的代码,用于绘制平面坐标系中两条相交线段的角平分线并将其旋转45°:
Sub DrawAngleBisector()
Dim line1 As AcadLine
Dim line2 As AcadLine
Dim intersectionPoint As Variant
Dim angleBisector1 As AcadLine
Dim angleBisector2 As AcadLine
Dim rotationAngle As Double
Dim rotatedAngleBisector As AcadLine
' 设置两条相交线段的起点和终点坐标
Dim line1StartPoint As Variant
line1StartPoint = Array(0, 0, 0)
Dim line1EndPoint As Variant
line1EndPoint = Array(5, 0, 0)
Dim line2StartPoint As Variant
line2StartPoint = Array(3, 1, 0)
Dim line2EndPoint As Variant
line2EndPoint = Array(3, 5, 0)
' 绘制两条线段
Set line1 = ThisDrawing.ModelSpace.AddLine(line1StartPoint, line1EndPoint)
Set line2 = ThisDrawing.ModelSpace.AddLine(line2StartPoint, line2EndPoint)
' 求两条线段的交点坐标
intersectionPoint = line1.IntersectWith(line2)
' 绘制角平分线
Set angleBisector1 = ThisDrawing.ModelSpace.AddLine(line1.StartPoint, intersectionPoint)
Set angleBisector2 = ThisDrawing.ModelSpace.AddLine(line1.EndPoint, intersectionPoint)
' 计算旋转角度
rotationAngle = 45
' 旋转角平分线
Set rotatedAngleBisector = angleBisector1.CopyRotate(angleBisector1.StartPoint, rotationAngle)
MsgBox "已绘制并旋转成功!"
End Sub
请注意,以上代码是基于AutoCAD VBA进行开发的,所以需要在AutoCAD软件中运行。代码中先定义了两条直线的起点和终点坐标,然后绘制两条线段。接下来使用IntersectWith方法获取两条线段的交点坐标,然后分别绘制两条角平分线。最后通过CopyRotate方法将其中一条角平分线按照指定的旋转角度进行旋转。
写一段CAD VBA代码,画出平面坐标系中的两条相交线段的角平分线,并将该角平分线以交点为原点旋转45°
### 回答1:
Sub DrawLine()
Dim X1, Y1, X2, Y2 As Double
Dim p1 As Point
Dim p2 As Point
Dim p3 As PointX1 = 0
Y1 = 0
X2 = 10
Y2 = 10Set p1 = CreatePoint(X1, Y1)
Set p2 = CreatePoint(X2, Y2)
Set p3 = IntersectPoint(p1, p2)Call DrawLineBy2Point(p1, p2)
Call DrawLineBy2Point(p3, RotatePoint(p3, 45))End Sub
### 回答2:
在CAD VBA中,我们可以使用CAD的工具和函数来绘制平面坐标系中的两条相交线段的角平分线,并将该角平分线以交点为原点旋转45°。以下是实现此功能的VBA代码:
首先,我们可以定义两个线段的起点和终点坐标,分别为线段1的起点坐标(x1,y1)、线段1的终点坐标(x2,y2)、线段2的起点坐标(x3,y3)和线段2的终点坐标(x4,y4)。
接下来,我们可以使用CAD的Line函数来绘制两条线段,分别为线段1和线段2:
Dim line1 As AcadLine
Set line1 = ThisDrawing.ModelSpace.AddLine(Point(x1, y1), Point(x2, y2))
Dim line2 As AcadLine
Set line2 = ThisDrawing.ModelSpace.AddLine(Point(x3, y3), Point(x4, y4))
然后,我们可以使用CAD的Angle函数来计算两条线段的夹角,并使用CAD的PolarPoint函数来得到该角的角平分线的终点坐标:
Dim angle As Double
angle = line1.GetAngleTo(line2)
Dim midpoint As AcadPoint
Set midpoint = ThisDrawing.ModelSpace.AddPoint(line1.StartPoint.PolarPoint(line1.Length / 2, angle / 2))
最后,我们可以使用CAD的Rotate函数将该角平分线以交点为原点旋转45°:
midpoint.Rotate midpoint, 45
通过以上的步骤,我们可以在CAD中绘制平面坐标系中的两条相交线段的角平分线,并将该角平分线以交点为原点旋转45°。
### 回答3:
以下是一个示例的CAD VBA代码,该代码用于绘制平面坐标系中两条相交线段的角平分线,并将该角平分线以交点为原点旋转45°。
```
Sub DrawAngleBisectorLine()
Dim line1_start As Variant
Dim line1_end As Variant
Dim line2_start As Variant
Dim line2_end As Variant
Dim angle_bisector_start As Variant
Dim angle_bisector_end As Variant
Dim intersection_point As Variant
Dim rotation_angle As Double
' 设置两条相交线段的起点和终点坐标
line1_start = ThisDrawing.Utility.GetPoint(, "输入线段1的起点:")
line1_end = ThisDrawing.Utility.GetPoint(line1_start, "输入线段1的终点:")
line2_start = ThisDrawing.Utility.GetPoint(, "输入线段2的起点:")
line2_end = ThisDrawing.Utility.GetPoint(line2_start, "输入线段2的终点:")
' 获取两条线段的交点
intersection_point = GetIntersection(line1_start, line1_end, line2_start, line2_end)
' 计算角平分线的起点和终点坐标
angle_bisector_start = intersection_point
angle_bisector_end = RotatePoint(intersection_point, intersection_point + ThisDrawing.Utility.GetOrthoVector, 45)
' 绘制角平分线
ThisDrawing.ModelSpace.AddLine angle_bisector_start, angle_bisector_end
End Sub
Function GetIntersection(p1 As Variant, p2 As Variant, p3 As Variant, p4 As Variant) As Variant
' 计算两条线段的交点坐标
Dim intersection_point As Variant
intersection_point = ThisDrawing.Utility.GetIntersectionPoint(p1, p2, p3, p4)
GetIntersection = intersection_point
End Function
Function RotatePoint(center As Variant, point As Variant, angle As Double) As Variant
' 将点以指定角度绕中心点旋转
Dim rotated_point As Variant
Dim radians As Double
radians = angle * 3.14159265358979 / 180 ' 将角度转换为弧度
rotated_point(0) = (point(0) - center(0)) * Math.Cos(radians) - (point(1) - center(1)) * Math.Sin(radians) + center(0)
rotated_point(1) = (point(0) - center(0)) * Math.Sin(radians) + (point(1) - center(1)) * Math.Cos(radians) + center(1)
RotatePoint = rotated_point
End Function
```
你可以将上述代码复制到CAD VBA编辑器中运行,按照提示输入两条相交线段的坐标,然后将会在模型空间中绘制出角平分线,以交点为原点旋转45°。
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