a.cpp:22:32: error: postfix ‘MyTime MyTime::operator++(MyTime&)’ must take ‘int’ as its argument MyTime operator++(MyTime &t){
时间: 2024-02-09 16:08:09 浏览: 32
这个错误提示是因为你在定义 MyTime 类的后置自增运算符时,传入的参数类型不正确。后置自增运算符应该只接受一个 int 类型的参数,而你传入的是一个 MyTime 类型的引用。
正确的写法应该是:
```c++
MyTime operator++(int){ // 注意参数为 int 类型
MyTime temp(hours, minutes, seconds);
seconds++;
if(seconds >= 60){
seconds -= 60;
minutes++;
if(minutes >= 60){
minutes -= 60;
hours++;
if(hours >= 24){
hours = 0;
}
}
}
return temp;
}
```
这样就可以解决这个错误了。
相关问题
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[ .reference_list ]
Write+a+program+to+evaluate+a+postfix+expression.+You+only+have+to+handle+four+kinds+of+operators:++
Sure! To evaluate a postfix expression, we can use a stack to keep track of the operands. Here's an example program in C++:
```
#include <iostream>
#include <stack>
#include <string>
using namespace std;
int evaluatePostfix(string exp) {
stack<int> s;
for (int i = 0; i < exp.length(); i++) {
if (isdigit(exp[i])) {
s.push(exp[i] - '0');
} else {
int op2 = s.top();
s.pop();
int op1 = s.top();
s.pop();
switch (exp[i]) {
case '+':
s.push(op1 + op2);
break;
case '-':
s.push(op1 - op2);
break;
case '*':
s.push(op1 * op2);
break;
case '/':
s.push(op1 / op2);
break;
}
}
}
return s.top();
}
int main() {
string exp = "23+4*";
cout << evaluatePostfix(exp) << endl; // Output: 14
return 0;
}
```
In this program, we iterate through the postfix expression character by character. If the character is a digit, we push it onto the stack. If it's an operator, we pop the top two operands from the stack, perform the operation, and push the result back onto the stack. Finally, we return the top element of the stack, which is the result of the expression.