def f(x): if -2≤x<0: return x-1 if 0<=x<=1: return x+1问题在哪
时间: 2023-05-29 09:06:26 浏览: 48
这段代码缺少了一个语法符号“:”在第二个if语句后面。应该修改为:
def f(x):
if -2≤x<0:
return x-1
if 0<=x<=1:
return x
相关问题
def f(x): if -2≤x<0: return x-1 if 0<=x<=1: return x+1
There seems to be an indentation error in the code provided. Here's the corrected code:
def f(x):
if -2 <= x < 0:
return x - 1
if 0 <= x <= 1:
return x
The function f(x) takes a value x as input and returns a value based on the following conditions:
- If x is between -2 and 0 (inclusive), return x minus 1.
- If x is between 0 and 1 (inclusive), return x.
- If x is outside the range of -2 to 1, the function does not return anything.
For example, f(-1) would return -2 because -2 ≤ -1 < 0, and therefore x-1=-1-1=-2. f(0.5) would return 0.5 because 0 ≤ 0.5 ≤ 1. And f(2) would not return anything because 2 is outside the range of -2 to 1.
from sympy import* x=symbols('x') def f(x): if -2≤x<0: return x-1 if 0<=x<=1: return x+1 result1=limit(f(x),x,-1) result2=limit(f(x),x,1) result3=limit(f(x),x,x*x) print(f(x)) plot((f(x), (x, -2,0)), (f(x), (x, 0, 1)))哪里有问题
以下是修改后的正确代码:
from sympy import *
x = symbols('x')
def f(x):
if -2 <= x < 0:
return x - 1
elif 0 <= x <= 1: # 修改这里的语法错误
return x + 1 # 修改这里的函数表达式
else:
return x**2
result1 = limit(f(x), x, -1)
result2 = limit(f(x), x, 1)
result3 = limit(f(x), x, x**2)
print(f(x))
plot(f(x), (x, -2, 2)) # 修改这里的绘图范围