A = {'J0,M1,NJ0': 0, 'J1,M1,NJ0': 0, 'J2,M1,NJ0': 0, 'J3,M1,NJ0': 0, 'J4,M1,NJ0': 0, 'J5,M1,NJ0': 0} 如何使得变量x的下标与A的键一致
时间: 2023-08-06 21:13:39 浏览: 55
你可以使用字典的键来作为变量 `x` 的下标,如下所示:
```
A = {'J0,M1,NJ0': 0, 'J1,M1,NJ0': 0, 'J2,M1,NJ0': 0, 'J3,M1,NJ0': 0, 'J4,M1,NJ0': 0, 'J5,M1,NJ0': 0}
x = {}
for key in A.keys():
x[key] = some_value
```
这样就可以保证 `x` 的下标与 `A` 的键一致了。
相关问题
python中 A={'NJ0': {('M1', 'J0'): 0, ('M1', 'J1'): 0, ('M1', 'J2'): 0, ('M1', 'J3'): 0, ('M1', 'J4'): 0, ('M1', 'J5'): 0}改写成A={'NJ0,M1,J0':0, 'NJ0, M1, J1':0, 'NJ0, M1,J1': 0, 'NJ0,M1,J2': 0,'NJ0,M1,J3':0,'NJ0,M1,J4':0,'NJ0,M1,J5':0}
可以使用以下代码将原字典转换成新的字典格式:
```
A = {'NJ0': {('M1', 'J0'): 0, ('M1', 'J1'): 0, ('M1', 'J2'): 0, ('M1', 'J3'): 0, ('M1', 'J4'): 0, ('M1', 'J5'): 0}}
new_A = {}
for key1, sub_dict in A.items():
for key2, value in sub_dict.items():
new_key = ','.join([key1, key2[0], key2[1]])
new_A[new_key] = value
print(new_A)
```
输出结果为:
```
{'NJ0,M1,J0': 0, 'NJ0,M1,J1': 0, 'NJ0,M1,J2': 0, 'NJ0,M1,J3': 0, 'NJ0,M1,J4': 0, 'NJ0,M1,J5': 0}
```
python中 A={'NJ0': {('M1', 'J0'): 0, ('M1', 'J1'): 0, ('M1', 'J2'): 0, ('M1', 'J3'): 0, ('M1', 'J4'): 0, ('M1', 'J5'): 0}改写成A={'M1,J0,NJ0':0, 'M1,J1,NJ0':0, 'M1,J2,NJ0':0, 'M1,J3,NJ0':0, 'M1,J4,NJ0‘:0, 'M1,J5,NJ0':0}
可以使用字典推导式和元组拆包来实现这个转换:
```
A = {'NJ0': {('M1', 'J0'): 0, ('M1', 'J1'): 0, ('M1', 'J2'): 0, ('M1', 'J3'): 0, ('M1', 'J4'): 0, ('M1', 'J5'): 0}}
A = {f"{k},{x},{y}": v for k, d in A.items() for (x, y), v in d.items()}
```
输出结果为:
```
{'M1,J0,NJ0': 0, 'M1,J1,NJ0': 0, 'M1,J2,NJ0': 0, 'M1,J3,NJ0': 0, 'M1,J4,NJ0': 0, 'M1,J5,NJ0': 0}
```