python推箱子代码详细讲解_python实现推箱子游戏
时间: 2023-10-30 18:04:47 浏览: 233
推箱子游戏是一种益智类的游戏,可以通过编程来实现。下面是一个简单的 Python 实现推箱子游戏的代码:
```python
# 定义地图
map_data = [
"#####",
"# #",
"#O #",
"# #",
"#####"
]
# 定义玩家初始位置
player_x = 1
player_y = 2
# 定义目标位置
goal_x = 3
goal_y = 2
# 定义箱子初始位置
box_x = 2
box_y = 2
# 游戏循环
while True:
# 绘制地图
for row in map_data:
print(row)
# 判断是否完成游戏
if box_x == goal_x and box_y == goal_y:
print("恭喜你,完成游戏!")
break
# 获取用户输入
direction = input("请输入移动方向(上:w,下:s,左:a,右:d):")
# 根据用户输入修改玩家位置和箱子位置
if direction == "w":
if map_data[player_y-1][player_x] != "#":
player_y -= 1
if box_x == player_x and box_y == player_y:
if map_data[box_y-1][box_x] != "#":
box_y -= 1
else:
player_y += 1
else:
continue
elif direction == "s":
if map_data[player_y+1][player_x] != "#":
player_y += 1
if box_x == player_x and box_y == player_y:
if map_data[box_y+1][box_x] != "#":
box_y += 1
else:
player_y -= 1
else:
continue
elif direction == "a":
if map_data[player_y][player_x-1] != "#":
player_x -= 1
if box_x == player_x and box_y == player_y:
if map_data[box_y][box_x-1] != "#":
box_x -= 1
else:
player_x += 1
else:
continue
elif direction == "d":
if map_data[player_y][player_x+1] != "#":
player_x += 1
if box_x == player_x and box_y == player_y:
if map_data[box_y][box_x+1] != "#":
box_x += 1
else:
player_x -= 1
else:
continue
```
上面的代码实现了一个简单的推箱子游戏,其中 `map_data` 是地图数据,`player_x` 和 `player_y` 是玩家初始位置,`goal_x` 和 `goal_y` 是目标位置,`box_x` 和 `box_y` 是箱子初始位置。游戏循环中先绘制地图,再判断是否完成游戏,然后获取用户输入,根据用户输入修改玩家位置和箱子位置,最后循环继续。注意在修改箱子位置时要判断是否撞墙,以及玩家是否能够推动箱子。
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