帮我用c语言写一段代码，函数名为Chars get_int；形式参数为const char *cs, Uint len, int *nump；Starting from cs, skip any proceed white space character, then read several consecutive non-space characters, that can form an int (an optional sign of + or - is allowed). The integer is saved at the address nump. The return value is a Chars which include the address of the first character of the the integer in the CS, and the number of characters appear in the integer (including the possible sign). If no integer appears at the beginning of the CS at addr (skipping starting spaces), then an empty Chars (with NULL address and 0 length) is returned.；The starting character of an integer should be + - or a digit. After the sign of + and - each character in the integer should be a digit.

好的，这是一个可以实现这一功能的代码片段：

#include <ctype.h>
#include <stdbool.h>
#include <stdio.h>

typedef struct {
  const char* addr;
  int len;
} Chars;

typedef unsigned int Uint;

Chars get_int(const char* cs, Uint len, int* nump) {
  Chars result;
  result.addr = NULL;
  result.len = 0;

  // 跳过开头的空白字符
  while (len > 0 && isspace(*cs)) {
    cs++;
    len--;
  }

  // 检查是否是负号或数字
  if (len > 0 && (*cs == '-' || *cs == '+' || isdigit(*cs))) {
    // 检查是否有负号
    bool negative = false;
    if (*cs == '-') {
      negative = true;
      cs++;
      len--;
    } else if (*cs == '+') {
      cs++;
      len--;
    }

    // 读取数字
    *nump = 0;
    while (len > 0 && isdigit(*cs)) {
      *nump = *nump * 10 + (*cs - '0');
      cs++;
      len--;
    }

    // 应用负号
    if (negative) {
      *nump = -*nump;
    }

    // 设置结果值
    result.addr = cs - result.len;
    result.len = cs - result.addr;
  }

  return result;
}

这段代码使用了 ctype.h 库中的函数 `isspace` 和 `isdigit` 来跳过空白字符和判断是否是数字。它使用了一个布尔变量来记录数字是否是负数，然后使用一个循环来读取连续的数字，并根据需要应用负号。最后，它设置结果值并返回。

希望这个代码片段能帮助到你。如果你有其他问题，请随时联系我。