用C语言写复数运算代码
时间: 2024-01-28 11:05:48 浏览: 20
以下是一个简单的复数运算代码示例,其中包含了加、减、乘、除和求模运算:
```c
#include <stdio.h>
#include <math.h>
typedef struct {
double real; // 实部
double imag; // 虚部
} Complex;
// 复数加法
Complex add(Complex a, Complex b) {
Complex c;
c.real = a.real + b.real;
c.imag = a.imag + b.imag;
return c;
}
// 复数减法
Complex sub(Complex a, Complex b) {
Complex c;
c.real = a.real - b.real;
c.imag = a.imag - b.imag;
return c;
}
// 复数乘法
Complex mul(Complex a, Complex b) {
Complex c;
c.real = a.real * b.real - a.imag * b.imag;
c.imag = a.real * b.imag + a.imag * b.real;
return c;
}
// 复数除法
Complex div(Complex a, Complex b) {
Complex c;
double denominator = b.real * b.real + b.imag * b.imag;
c.real = (a.real * b.real + a.imag * b.imag) / denominator;
c.imag = (a.imag * b.real - a.real * b.imag) / denominator;
return c;
}
// 求复数模
double abs(Complex a) {
return sqrt(a.real * a.real + a.imag * a.imag);
}
int main() {
Complex a = {1.0, 2.0};
Complex b = {3.0, 4.0};
Complex c = add(a, b);
printf("a + b = %.1f + %.1fi\n", c.real, c.imag);
c = sub(a, b);
printf("a - b = %.1f + %.1fi\n", c.real, c.imag);
c = mul(a, b);
printf("a * b = %.1f + %.1fi\n", c.real, c.imag);
c = div(a, b);
printf("a / b = %.1f + %.1fi\n", c.real, c.imag);
double mod = abs(a);
printf("|a| = %.1f\n", mod);
return 0;
}
```
该代码定义了一个名为Complex的结构体,包含了实部和虚部两个变量。然后定义了加、减、乘、除和求模等函数,分别实现了对两个复数进行相应运算。在main函数中,创建了两个复数a和b,分别调用以上函数进行运算,并输出结果。