def switch(option): funcdic = { 1: lambda: searchmode(),
时间: 2023-06-27 17:04:06 浏览: 48
2: lambda: editmode(), 3: lambda: exitprogram() } func = funcdic.get(option, lambda: print("Invalid option")) func()
这是一个 Python 中用字典实现 switch-case 语句的例子。其中,根据传入的 option 值,从 funcdic 字典中取出对应的 lambda 函数,并执行该函数。如果 option 值不在字典的 key 中,则会执行一个默认的 lambda 函数,输出 "Invalid option"。这种方式可以实现类似于 switch-case 的多分支选择,同时也可以避免使用大量的 if-elif 语句造成代码冗长。
相关问题
if i == n - 1: now = s - already 用lambda替换
可以使用lambda表达式将这段代码转换为一行代码:
```python
now = (lambda x: s - already)(n - 1 - i)
```
lambda表达式的语法为:`lambda arguments : expression`,其中arguments是传入函数的参数,expression是lambda函数的返回值。在这个例子中,我们将`n - 1 - i`作为参数传入lambda函数,函数返回`s - already`的值,相当于原来的代码中的`now = s - already`。
if index==1: count = count_conditions( teacher_arr, lambda row: row[3] <24, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==2: count = count_conditions( teacher_arr, lambda row: row[3] >24 and lambda row: row[3] <30, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==3: count = count_conditions( teacher_arr, lambda row: row[3] >29 and lambda row: row[3] <35, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==4: count = count_conditions( teacher_arr, lambda row: row[3] >34 and lambda row: row[3] <40, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==5: count = count_conditions( teacher_arr, lambda row: row[3] >39 and lambda row: row[3] <45, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==6: count = count_conditions( teacher_arr, lambda row: row[3] >44 and lambda row: row[3] <50, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==7: count = count_conditions( teacher_arr, lambda row: row[3] >49 and lambda row: row[3] <55, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==9: count = count_conditions( teacher_arr, lambda row: row[3] >=60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass 优化代码
您的代码可以通过使用循环和列表,来避免重复的代码。以下是一种重构方案:
```
age_ranges = [(0, 24), (24, 30), (30, 35), (35, 40), (40, 45), (45, 50), (50, 55), (55, 60), (60, 100)]
counts = []
for i, age_range in enumerate(age_ranges):
if i == index - 1:
count = count_conditions(teacher_arr,
lambda row: age_range[0] < row[3] < age_range[1],
lambda row: row[11] == item1,
lambda row: row[8] == '专任教师')
counts.append(count)
else:
counts.append(0)
```
这样,您就可以通过循环和列表,避免重复的代码,并且可以更加清晰和易读。