帮我写一段贪吃蛇的代码
时间: 2024-03-04 20:25:22 浏览: 109
好的,这是用 Python 实现的贪吃蛇游戏代码:
```
import turtle
import time
# 设置窗口
win = turtle.Screen()
win.title("贪吃蛇")
win.bgcolor("black")
win.setup(width=600, height=600)
# 蛇的头部
head = turtle.Turtle()
head.speed(0)
head.shape("square")
head.color("white")
head.penup()
head.goto(0,0)
head.direction = "stop"
# 食物
food = turtle.Turtle()
food.speed(0)
food.shape("circle")
food.color("red")
food.penup()
food.goto(0,100)
# 设置移动函数
def move():
if head.direction == "up":
y = head.ycor()
head.sety(y + 20)
if head.direction == "down":
y = head.ycor()
head.sety(y - 20)
if head.direction == "left":
x = head.xcor()
head.setx(x - 20)
if head.direction == "right":
x = head.xcor()
head.setx(x + 20)
# 设置控制函数
def go_up():
if head.direction != "down":
head.direction = "up"
def go_down():
if head.direction != "up":
head.direction = "down"
def go_left():
if head.direction != "right":
head.direction = "left"
def go_right():
if head.direction != "left":
head.direction = "right"
# 绑定键盘事件
win.listen()
win.onkeypress(go_up, "Up")
win.onkeypress(go_down, "Down")
win.onkeypress(go_left, "Left")
win.onkeypress(go_right, "Right")
# 主循环
while True:
win.update()
# 碰到食物
if head.distance(food) < 20:
x = food.xcor()
y = food.ycor()
food.goto(x, y)
move()
time.sleep(0.1)
win.mainloop()
```
希望对你有所帮助!
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