c语言模拟扑克牌自动发牌

好的，下面是一个简单的 C 语言程序，可以模拟扑克牌自动发牌的过程：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define NUM_SUITS 4
#define NUM_RANKS 13
#define NUM_CARDS 52

int main()
{
    // 定义扑克牌的花色和点数
    const char* suits[NUM_SUITS] = {"Spades", "Hearts", "Diamonds", "Clubs"};
    const char* ranks[NUM_RANKS] = {"Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King"};

    // 定义一个扑克牌的数组
    int deck[NUM_CARDS];

    // 生成一个初始的扑克牌数组
    int i, j, k;
    for (i = 0; i < NUM_SUITS; i++) {
        for (j = 0; j < NUM_RANKS; j++) {
            deck[NUM_RANKS*i+j] = j;
        }
    }

    // 打乱扑克牌数组的顺序
    srand(time(NULL));
    for (i = 0; i < NUM_CARDS; i++) {
        j = rand() % NUM_CARDS;
        k = deck[i];
        deck[i] = deck[j];
        deck[j] = k;
    }

    // 发牌
    int num_players = 4;
    int num_cards_per_player = NUM_CARDS / num_players;
    for (i = 0; i < num_players; i++) {
        printf("Player %d's cards:\n", i+1);
        for (j = 0; j < num_cards_per_player; j++) {
            int card_index = i*num_cards_per_player+j;
            int suit_index = deck[card_index] / NUM_RANKS;
            int rank_index = deck[card_index] % NUM_RANKS;
            printf("%s of %s\n", ranks[rank_index], suits[suit_index]);
        }
        printf("\n");
    }

    return 0;
}

这个程序定义了扑克牌的花色和点数，然后生成一个初始的扑克牌数组。接着，使用 `srand()` 函数和 `rand()` 函数打乱扑克牌数组的顺序。最后，按照设定的玩家数和每个玩家的牌数，发牌并输出每个玩家手中的牌。