用C语言模拟扑克自动发牌

好的，这是一个比较简单的扑克自动发牌的 C 语言程序示例：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define CARD_NUM 52
#define PLAYER_NUM 4

void shuffle(int* deck, int n) {
    srand(time(NULL));
    for (int i = n - 1; i > 0; i--) {
        int j = rand() % (i + 1);
        int temp = deck[i];
        deck[i] = deck[j];
        deck[j] = temp;
    }
}

void print_card(int card) {
    const char* suits[] = {"Spades", "Hearts", "Diamonds", "Clubs"};
    const char* ranks[] = {"Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King"};
    int suit = card / 13;
    int rank = card % 13;
    printf("%s of %s\n", ranks[rank], suits[suit]);
}

int main() {
    int deck[CARD_NUM];
    for (int i = 0; i < CARD_NUM; i++) {
        deck[i] = i;
    }
    shuffle(deck, CARD_NUM);
    int player_cards[PLAYER_NUM][CARD_NUM / PLAYER_NUM];
    for (int i = 0; i < PLAYER_NUM; i++) {
        printf("Player %d:\n", i + 1);
        for (int j = 0; j < CARD_NUM / PLAYER_NUM; j++) {
            player_cards[i][j] = deck[CARD_NUM / PLAYER_NUM * i + j];
            print_card(player_cards[i][j]);
        }
        printf("\n");
    }
    return 0;
}

程序中定义了两个常量 `CARD_NUM` 和 `PLAYER_NUM`，分别表示一副扑克牌的数量和玩家数量。`shuffle` 函数用于洗牌，采用了随机交换的方法。`print_card` 函数用于打印一张扑克牌的花色和点数。在 `main` 函数中，先生成一副牌并洗牌，然后按照玩家数量将牌发到不同的玩家手中，并打印每个玩家的牌。