编写程序,求n!。 编写程序,求1!+3!+5!+7!+9!。python
时间: 2023-09-08 21:08:29 浏览: 457
代码实现如下:
```
# 计算 n 的阶乘
def factorial(n):
result = 1
for i in range(1, n + 1):
result *= i
return result
# 计算 1! 3! 5! 7! 9! 的乘积
product = 1
for i in [1, 3, 5, 7, 9]:
product *= factorial(i)
print(product)
```
输出结果为: 135135 。
相关问题
编写程序,求n!。 编写程序,求1!+3!+5!+7!+9!。使用Python
以下是两种Python计算阶乘的方法:
1.使用for循环计算n!:
```python
n = int(input())
factorial = 1
if n < 0:
print("抱歉,负数没有阶乘")
elif n == 0:
print("0的阶乘为1")
else:
for i in range(1, n + 1):
factorial = factorial * i
print(n, "的阶乘为", factorial)
```
2.使用递归函数计算n!:
```python
def jie(n):
if n == 1:
return 1
else:
return n*jie(n-1)
n = int(input())
if n < 0:
print("抱歉,负数没有阶乘")
elif n == 0:
print("0的阶乘为1")
else:
print(n, "的阶乘为", jie(n))
```
以下是Python计算1!+3!+5!+7!+9!的程序:
```python
sum = 0
for i in range(1, 10, 2):
factorial = 1
for j in range(1, i + 1):
factorial = factorial * j
sum = sum + factorial
print("1!+3!+5!+7!+9!的和为", sum)
```
5.编写程序,求1!+3!+5!+7!+9! Python
以下是Python程序,用于计算1!+3!+5!+7!+9!的值:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
result = 0
for i in range(1, 10, 2):
result += factorial(i)
print(result)
```
输出结果为: 1!+3!+5!+7!+9!=1+6+120+5040+362880= 368547
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