在vscode+platformio中打开项目没有切换非活跃区着色 怎么设置c++ 才能实现
时间: 2024-05-15 16:19:52 浏览: 16
在VSCode中,可以通过在settings.json文件中添加以下配置来开启非活跃区着色:
```
"editor.tokenColorCustomizations": {
"textMateRules": [
{
"scope": "inactiveRegion",
"settings": {
"foreground": "#CCCCCC"
}
}
]
}
```
将上述代码复制到settings.json文件中,保存后重新打开VSCode,即可看到非活跃区已经被着色。
另外,如果想要设置C语言的着色,在VSCode中可以安装C/C++插件,并在settings.json文件中添加以下配置:
```
"files.associations": {
"*.c": "c",
"*.h": "c"
}
```
这样,VSCode就会将.c和.h文件识别为C语言文件并启用对应的着色方案。
相关问题
图着色问题C++实现
以下是一个使用C++实现图着色问题的示例代码:
```cpp
#include <iostream>
#include <list>
#include <vector>
using namespace std;
class Graph {
int V;
list<int> *adj;
public:
Graph(int V) {
this->V = V;
adj = new list<int>[V];
}
void addEdge(int v, int w) {
adj[v].push_back(w);
adj[w].push_back(v);
}
bool isSafe(int v, vector<int>& color, int c) {
for (auto it = adj[v].begin(); it != adj[v].end(); ++it) {
if (color[*it] == c) {
return false;
}
}
return true;
}
bool graphColoringUtil(vector<int>& color, int m, int v) {
if (v == V) {
return true;
}
for (int c = 1; c <= m; c++) {
if (isSafe(v, color, c)) {
color[v] = c;
if (graphColoringUtil(color, m, v + 1)) {
return true;
}
color[v] = 0;
}
}
return false;
}
bool graphColoring(int m) {
vector<int> color(V, 0);
if (graphColoringUtil(color, m, 0)) {
cout << "Graph can be colored with at most " << m << " colors." << endl;
cout << "Coloring scheme: ";
for (int i = 0; i < V; i++) {
cout << color[i] << " ";
}
cout << endl;
return true;
} else {
cout << "Graph cannot be colored with " << m << " colors." << endl;
return false;
}
}
};
int main() {
int V, E, m;
cout << "Enter the number of vertices in the graph: ";
cin >> V;
cout << "Enter the number of edges in the graph: ";
cin >> E;
Graph g(V);
cout << "Enter the edges (vertex pairs):" << endl;
for (int i = 0; i < E; i++) {
int v, w;
cin >> v >> w;
g.addEdge(v, w);
}
cout << "Enter the maximum number of colors: ";
cin >> m;
g.graphColoring(m);
return 0;
}
```
图的着色问题c++语言实现
好的,我明白了。关于图的着色问题在C语言中的实现,通常会利用贪心算法来求解。具体思路是首先将所有节点按照度数从大到小排序,并将每个节点的颜色初始化为0。然后依次对每个节点进行着色,对于当前节点,检查其邻居节点的颜色,如果邻居节点的某个颜色未被使用,则将当前节点着上该颜色,否则继续检查下一个颜色,直到找到未被使用的颜色为止。最后得到的着色结果就是一种合法的着色方案。