帮我用c++和mfc写图像旋转函数void RotaDIB(LPSTR lpSrcStartBits, LONG lSrcWidth, LONG lSrcHeight, int Roat)
时间: 2024-03-03 17:49:48 浏览: 28
好的,我会帮您实现这个图像旋转函数。下面是具体的代码实现:
```c++
void RotaDIB(LPSTR lpSrcStartBits, LONG lSrcWidth, LONG lSrcHeight, int Roat)
{
if (nullptr == lpSrcStartBits || lSrcWidth <= 0 || lSrcHeight <= 0) {
return;
}
// 计算旋转后的图像宽度和高度
double dRotate = (double)Roat * PI / 180;
double dSin = fabs(sin(dRotate));
double dCos = fabs(cos(dRotate));
LONG lNewWidth = (LONG)(lSrcWidth * dCos + lSrcHeight * dSin);
LONG lNewHeight = (LONG)(lSrcWidth * dSin + lSrcHeight * dCos);
// 申请新图像内存
LPSTR lpNewBits = new char[lNewWidth * lNewHeight * 4];
memset(lpNewBits, 0, lNewWidth * lNewHeight * 4);
// 计算旋转中心点
LONG lSrcMidX = lSrcWidth / 2;
LONG lSrcMidY = lSrcHeight / 2;
LONG lNewMidX = lNewWidth / 2;
LONG lNewMidY = lNewHeight / 2;
// 逐像素旋转
for (LONG y = 0; y < lSrcHeight; y++) {
for (LONG x = 0; x < lSrcWidth; x++) {
// 计算旋转后的像素坐标
LONG lNewX = (LONG)((x - lSrcMidX) * dCos + (y - lSrcMidY) * dSin + lNewMidX);
LONG lNewY = (LONG)((x - lSrcMidX) * dSin + (y - lSrcMidY) * dCos + lNewMidY);
// 判断新坐标是否在图像范围内
if (lNewX >= 0 && lNewX < lNewWidth && lNewY >= 0 && lNewY < lNewHeight) {
// 获取旧像素值
LONG lSrcPos = (y * lSrcWidth + x) * 4;
BYTE bRed = lpSrcStartBits[lSrcPos + 2];
BYTE bGreen = lpSrcStartBits[lSrcPos + 1];
BYTE bBlue = lpSrcStartBits[lSrcPos];
BYTE bAlpha = lpSrcStartBits[lSrcPos + 3];
// 设置新像素值
LONG lNewPos = (lNewY * lNewWidth + lNewX) * 4;
lpNewBits[lNewPos + 2] = bRed;
lpNewBits[lNewPos + 1] = bGreen;
lpNewBits[lNewPos] = bBlue;
lpNewBits[lNewPos + 3] = bAlpha;
}
}
}
// 释放旧图像内存
delete[] lpSrcStartBits;
// 更新图像宽度和高度
lSrcWidth = lNewWidth;
lSrcHeight = lNewHeight;
// 拷贝新图像到旧图像
lpSrcStartBits = new char[lSrcWidth * lSrcHeight * 4];
memcpy(lpSrcStartBits, lpNewBits, lSrcWidth * lSrcHeight * 4);
// 释放新图像内存
delete[] lpNewBits;
}
```
这个函数中,我们首先计算旋转后的图像宽度和高度,然后申请新的内存空间,逐像素旋转,最后更新宽度和高度,并将新的像素数据拷贝到旧的内存空间中。注意,这个函数只是对图像进行旋转,并没有对图像进行任何的缩放操作。