c sharp 关于流量压力和开口度的回归模型实例
时间: 2024-05-01 20:19:13 浏览: 68
以下是一个关于流量压力和开口度回归模型的 C# 实例代码```csharp
using System;
namespace RegressionModel
{
class Program
{
static void Main(string[] args)
{
// 输入数据
double[] flow = { 10, 20, 30, 40, 50 };
double[] pressure = { 20, 30, 40, 50, 60 };
int n = flow.Length;
// 计算平均值
double flowMean = Mean(flow);
double pressureMean = Mean(pressure);
// 计算方差
double flowVar = Variance(flow, flowMean);
double pressureVar = Variance(pressure, pressureMean);
// 计算协方差
double cov = Covariance(flow, pressure, flowMean, pressureMean);
// 计算斜率和截距
double slope = cov / flowVar;
double intercept = pressureMean - slope * flowMean;
// 输出结果
Console.WriteLine("Regression equation: pressure = {0} * flow + {1}", slope, intercept);
Console.ReadLine();
}
// 计算平均值
static double Mean(double[] data)
{
double sum = 0;
int n = data.Length;
for (int i = 0; i < n; i++)
{
sum += data[i];
}
return sum / n;
}
// 计算方差
static double Variance(double[] data, double mean)
{
double sum = 0;
int n = data.Length;
for (int i = 0; i < n; i++)
{
sum += Math.Pow(data[i] - mean, 2);
}
return sum / (n - 1);
}
// 计算协方差
static double Covariance(double[] x, double[] y, double xMean, double yMean)
{
double sum = 0;
int n = x.Length;
for (int i = 0; i < n; i++)
{
sum += (x[i] - xMean) * (y[i] - yMean);
}
return sum / (n - 1);
}
}
}
```
这个代码使用了最小二乘法来计算斜率和截距,从而得到回归方程。