在8086环境中汇编用递归实现斐波那契数列并显示每一项的数值

好的，下面是汇编代码实现斐波那契数列的递归算法，并显示每一项的值：

.model small
.stack 100h

.data
    msg db "Fibonacci sequence up to 10 terms:$"
    term db "Term ", 0
    value db "Value = ", 0

.code
main proc
    mov ax, @data
    mov ds, ax

    ; Display message
    mov ah, 9
    lea dx, msg
    int 21h

    ; Calculate and display Fibonacci sequence up to 10 terms
    mov cx, 10 ; Number of terms
    mov bx, 0 ; First term
    mov dx, 1 ; Second term
    mov si, 2 ; Current term count

    ; Display first term
    mov ah, 9
    lea dx, term
    int 21h
    mov ah, 2
    mov dl, bl
    int 21h
    mov dl, 0dh
    int 21h
    mov dl, 0ah
    int 21h

    ; Display second term
    mov ah, 9
    lea dx, term
    int 21h
    mov ah, 2
    mov dl, dl
    int 21h
    mov dl, 0dh
    int 21h
    mov dl, 0ah
    int 21h

    ; Calculate and display remaining terms
    mov ah, 9
    lea dx, term
    int 21h
    call fibonacci
    jmp exit

fibonacci proc
    push bp
    mov bp, sp
    sub sp, 2 ; Make room for return address

    ; Get current term count
    mov ax, si

    ; Check if all terms have been calculated
    cmp ax, cx
    jge done

    ; Calculate next term
    mov ax, bx
    add ax, dx
    mov bx, dx
    mov dx, ax

    ; Display current term
    mov ah, 9
    lea dx, term
    int 21h
    mov ah, 2
    mov dl, al
    int 21h
    mov dl, 0dh
    int 21h
    mov dl, 0ah
    int 21h

    ; Increment current term count
    inc si

    ; Call fibonacci recursively
    call fibonacci

done:
    ; Clean up stack and return
    add sp, 2
    pop bp
    ret
fibonacci endp

exit:
    ; Display newline and exit program
    mov dl, 0dh
    int 21h
    mov dl, 0ah
    int 21h
    mov ah, 4ch
    int 21h
main endp

end main

以上代码使用 `bx` 和 `dx` 寄存器来存储斐波那契数列中的前两项，使用 `si` 寄存器来跟踪当前项的数量，并使用递归算法来计算并显示每一项的值。请注意，这个代码只计算并显示斐波那契数列的前10项，如果需要更多的项，需要修改 `cx` 和 `msg` 中的值。