写一个纸牌比大小的python程序,谁大谁就获胜

以下是一个简单的纸牌大小比较的 Python 程序：

import random

# 创建一副扑克牌
def create_deck():
    suits = ['hearts', 'diamonds', 'clubs', 'spades']
    ranks = {'two':2, 'three':3, 'four':4, 'five':5, 'six':6, 'seven':7, 
             'eight':8, 'nine':9, 'ten':10, 'jack':11, 'queen':12, 'king':13, 'ace':14}
    deck = []
    for suit in suits:
        for rank, value in ranks.items():
            deck.append({'suit': suit, 'rank': rank, 'value': value})
    random.shuffle(deck)
    return deck

# 通过值来比较两张牌
def compare_cards(card1, card2):
    if card1['value'] > card2['value']:
        return 'player1'
    elif card1['value'] < card2['value']:
        return 'player2'
    else:
        return 'tie'

# 玩家抽一张牌
def draw_card(deck):
    return deck.pop()

# 游戏主循环
def main():
    deck = create_deck()
    player1_card = draw_card(deck)
    player2_card = draw_card(deck)
    
    print(f"Player 1 draws {player1_card['rank']} of {player1_card['suit']}")
    print(f"Player 2 draws {player2_card['rank']} of {player2_card['suit']}")
    
    winner = compare_cards(player1_card, player2_card)
    if winner == 'player1':
        print("Player 1 wins!")
    elif winner == 'player2':
        print("Player 2 wins!")
    else:
        print("It's a tie!")
        
# 运行游戏
main()

运行结果示例：

Player 1 draws five of diamonds
Player 2 draws jack of hearts
Player 2 wins!