reshape四维数组
时间: 2023-10-02 17:13:29 浏览: 157
对于一个四维数组,可以使用reshape函数改变其形状。reshape函数的用法如下:
numpy.reshape(a, newshape, order='C')
其中,a是要进行形状改变的数组,newshape是新的形状,order是可选参数,表示新数组的元素在内存中的存储顺序。默认为C,表示按行存储。另外还有F表示按列存储。
以下是一个例子,将一个4x3x2x2的四维数组改变成2x12x2x1的四维数组:
```python
import numpy as np
a = np.arange(0, 48).reshape(4, 3, 2, 2)
print('原数组:')
print(a)
b = np.reshape(a, (2, 12, 2, 1))
print('改变后的数组:')
print(b)
```
输出结果为:
```
原数组:
[[[[ 0 1]
[ 2 3]]
[[ 4 5]
[ 6 7]]
[[ 8 9]
[10 11]]]
[[[12 13]
[14 15]]
[[16 17]
[18 19]]
[[20 21]
[22 23]]]
[[[24 25]
[26 27]]
[[28 29]
[30 31]]
[[32 33]
[34 35]]]
[[[36 37]
[38 39]]
[[40 41]
[42 43]]
[[44 45]
[46 47]]]]
改变后的数组:
[[[[ 0]
[ 1]]
[[ 2]
[ 3]]
[[ 4]
[ 5]]
[[ 6]
[ 7]]
[[ 8]
[ 9]]
[[10]
[11]]
[[12]
[13]]
[[14]
[15]]
[[16]
[17]]
[[18]
[19]]
[[20]
[21]]
[[22]
[23]]]
[[[24]
[25]]
[[26]
[27]]
[[28]
[29]]
[[30]
[31]]
[[32]
[33]]
[[34]
[35]]
[[36]
[37]]
[[38]
[39]]
[[40]
[41]]
[[42]
[43]]
[[44]
[45]]
[[46]
[47]]]]
```
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