verilog,用数码管实现流水灯
时间: 2023-12-03 13:03:55 浏览: 152
以下是Verilog代码实现数码管流水灯:
```
module digit_led(
input clk,
output reg [6:0] digit,
output reg [3:0] seg
);
reg [25:0] counter;
reg [2:0] led;
always @ (posedge clk) begin
counter <= counter + 1;
if (counter == 500000) begin
counter <= 0;
led <= led + 1;
if (led == 8) begin
led <= 0;
end
end
end
always @ (led) begin
case (led)
0: begin
digit <= 7'b100_0000;
end
1: begin
digit <= 7'b010_0000;
end
2: begin
digit <= 7'b001_0000;
end
3: begin
digit <= 7'b000_1000;
end
4: begin
digit <= 7'b000_0100;
end
5: begin
digit <= 7'b000_0010;
end
6: begin
digit <= 7'b000_0001;
end
7: begin
digit <= 7'b000_0000;
end
endcase
end
always @ (digit) begin
case (digit)
7'b100_0000: begin
seg <= 4'b0111;
end
7'b010_0000: begin
seg <= 4'b0001;
end
7'b001_0000: begin
seg <= 4'b1011;
end
7'b000_1000: begin
seg <= 4'b0011;
end
7'b000_0100: begin
seg <= 4'b0101;
end
7'b000_0010: begin
seg <= 4'b1100;
end
7'b000_0001: begin
seg <= 4'b1101;
end
7'b000_0000: begin
seg <= 4'b1111;
end
endcase
end
endmodule
```
这里使用了一个计数器 `counter` 和一个变量 `led` 来控制数码管的显示,每当计数器达到一定值时,`led` 加 1,然后根据 `led` 的值来显示相应的数码管和数码的段码。在这个例子中,每个数码管都是由 7 个 LED 组成,因此 `digit` 变量使用了 7 位二进制来控制数码管的 LED 状态,而 `seg` 变量则使用了 4 位二进制来控制数码管的段码。
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