grouping expressions sequence is empty, and 'c.pay_ord_amt_tb' is not an aggregate function.

这是一个 SQL 报错信息，它的意思是：在一个 GROUP BY 子句中，分组表达式的值为空，并且 'c.pay_ord_amt_tb' 不是聚合函数。

解决这个问题需要检查 GROUP BY 子句中的分组表达式是否正确，以及查询中是否正确使用了聚合函数。可能需要检查查询中的其他部分，如 SELECT、FROM、WHERE 子句等，以查找问题的根本原因。

相关问题

tf.add_to_collection

(tf.GraphKeys, var_list)

The tf.add_to_collection() function is used to add variables, tensors, or operations to a collection. A collection is a grouping of objects in a TensorFlow graph that can be retrieved or modified as a unit.

The function takes two arguments:

1. GraphKeys: This is a predefined collection of keys that TensorFlow provides. Some examples include GLOBAL_VARIABLES, TRAINABLE_VARIABLES, and LOSSES. These keys are used to group objects by their purpose or properties.

2. var_list: This is a list of variables, tensors, or operations that will be added to the collection.

For example, to add a variable to the GLOBAL_VARIABLES collection, you would use the following code:

import tensorflow as tf

# Define a variable
my_var = tf.Variable(0.0, name='my_variable')

# Add the variable to the GLOBAL_VARIABLES collection
tf.add_to_collection(tf.GraphKeys.GLOBAL_VARIABLES, my_var)

Once an object is added to a collection, it can be retrieved using the tf.get_collection() function. For example, to retrieve all variables in the GLOBAL_VARIABLES collection, you would use the following code:

# Get all variables in the GLOBAL_VARIABLES collection
global_vars = tf.get_collection(tf.GraphKeys.GLOBAL_VARIABLES)

hiveSql 报错 Grouping sets expression is not in GROUP BY key.

Hive SQL报这个错误通常是因为你在查询中尝试使用GROUPING SETS操作符对数据进行分组，但是该操作需要有一个明确的GROUP BY子句，以便确定如何组合行并计算聚合函数。GROUP BY子句指定的是哪些列应参与分组。

GROUPING SETS语法允许你指定一组列的集合来生成所有可能的分组，比如`SELECT column1, column2 GROUPING SETS ((column1), (column2))`。然而，如果在没有明确指定GROUP BY的情况下使用了GROUPING SETS，Hive会抛出这个错误，因为你没有告诉它依据哪些键来组织数据。

解决这个问题，你需要确保GROUP BY部分包含了GROUPING SETS表达式中列出的所有列或是一个合适的汇总，如COUNT()等，以便Hive能够理解如何进行分组。例如：

SELECT column1, column2, COUNT(*) 
FROM table_name
GROUP BY column1, column2
GROUPING SETS ((column1), (column2));