Julian day 计算代码 matlab
时间: 2024-01-10 15:03:27 浏览: 39
以下是使用 Matlab 计算 Julian day 的代码示例:
```matlab
function jd = julian_day(year, month, day, hour, minute, second)
% Compute Julian day given year, month, day, hour, minute, and second.
% Constants
J1970 = 2440588; % Julian day on January 1, 1970
J2000 = 2451545; % Julian day on January 1, 2000
% Convert hour, minute, and second to fractional days
frac_day = (hour + minute/60 + second/3600) / 24;
% Calculate Julian day
if month <= 2
year = year - 1;
month = month + 12;
end
A = floor(year/100);
B = 2 - A + floor(A/4);
jd = floor(365.25*(year+4716)) + floor(30.6001*(month+1)) + ...
day + B - 1524.5 + frac_day;
% Adjust for time zone
jd = jd - (8/24); % For example, PST is 8 hours behind UTC
% Adjust to start at midnight (rather than noon)
jd = jd - 0.5;
% Adjust to start at J2000 instead of J1970
jd = jd - (J1970 - J2000);
end
```
您可以通过调用 `julian_day(year, month, day, hour, minute, second)` 函数,传入年、月、日、时、分、秒等参数,计算出 Julian day。请注意,该代码使用的时区为 UTC-8(太平洋标准时间),您可以根据需要进行调整。