c语言编写程序求无理数e输出计算公e=1＋1/1！＋1/！2+1/3+...＋1/n！1当1/n！＜0.000001时e＝2.718282

以下是C语言编写程序求无理数e输出计算公式e=1＋1/1！＋1/！2+1/3+...＋1/n！1当1/n！＜0.000001时e＝2.718282的例子：

#include <stdio.h>

int main() {
    int n = 1;
    double e = 1, factorial = 1;
    while (1) {
        factorial *= n;
        double term = 1.0 / factorial;
        if (term < 0.000001) {
            break;
        }
        e += term;
        n++;
    }
    printf("e = %lf\n", e);
    return 0;
}

运行结果为：

e = 2.718282