Delta AH500QS_O_SC快速入门指南

需积分: 9 0 下载量 133 浏览量 更新于2024-07-26 收藏 5.1MB PDF 举报
"Delta_AH500QS_O_SC" 这篇资源是关于Delta AH500QS系列PLC的快速入门手册,旨在帮助用户快速理解和操作这款工业自动化控制器。手册涵盖了从系统架构到程序规划撰写的主要步骤,适合初次接触AH500系列的新手。 第1章简介: 1.1手册内容简介: 手册详细介绍了AH500系列的不同类型的手册,包括硬件手册、操作手册、程序手册、模块手册以及运动控制模块手册,这些手册分别针对不同需求提供全面的指导。此外,还有专门的ISPSoft和PMSoft使用手册,用于辅助用户进行编程和运动控制设置。 1.2系统架构简介: 这部分简述了AH500PLC的基本结构,可能涉及CPU模块、I/O模块、电源模块以及其他扩展模块的组合,以及它们在系统中的相互作用。 1.3主机运作介绍: 这部分将深入解释AH500PLC的运行机制,包括数据处理、通信功能、故障检测和诊断等。 第2章程序规划撰写: 2.1准备工作: 详细列出了开始编程前需要准备的硬件、软件和工具,如PLC模块、电脑、编程软件ISPSoft或PMSoft,以及可能需要的连接线缆和端子。 2.2安装与配线: 这部分介绍了如何正确安装模块和端子,以及各种I/O模块的接线方法,包括电源、数字输入/输出和模拟输入/输出模块。 2.3范例说明和项目建立: 提供了实例来演示编程过程,并指导用户如何创建项目,规划硬件架构,定义全局符号,建立功能块,以及编写主程序。 第3章程序规划撰写(部分重复,可能是误复制): 3.1COMMGR设定: 讲解了如何启动和配置COMMGR(通信管理器),这是用于设置PLC与电脑或其他设备通信的重要工具。 3.2专案下载: 指导用户如何设定项目通讯参数,下载硬件设定和程序内容到PLC,确保程序能够正确地上传和下载。 3.3程序监视与除错: 这部分介绍了如何监控程序执行情况,以及进行程序和系统的调试,帮助用户查找和解决潜在问题。 总结来说,Delta AH500QS快速入门手册为用户提供了一个逐步学习和实践的平台,从基础的系统了解、硬件安装到程序设计和调试,全方位地支持用户掌握这款PLC的使用。通过这个手册,用户可以快速上手并高效地进行工业自动化系统的开发和维护。

clear all; clc; du = pi/180; a = [0+0.001, 185+0.0079, 0+0.005, 120+0.12]; alpha = [pi/2+0.003, 0+0.001, pi/2+0.005, pi/2]; d = [0+0.001, 0+0.0079, 90+0.005, 0+0.12]; theta = [90*du+0.02, 0, 0.023, 0.08]; beta = zeros(1, 4)+0; L1(1) = Link('d', d(1), 'a', a(1), 'alpha', alpha(1), 'qlim', [180*du, 365*du], 'modified'); L1(2) = Link('d', d(2), 'a', a(2), 'alpha', alpha(2), 'qlim', [3*du, 63*du], 'modified'); L1(3) = Link('d', d(3), 'a', a(3), 'alpha', alpha(3), 'qlim', [60*du, 120*du], 'modified'); L1(4) = Link('d', d(4), 'a', a(4), 'alpha', alpha(4), 'qlim', [230*du, 326*du], 'modified'); Needle = SerialLink(L1, 'name', 'Needle'); T1 = DH(1, a(1), alpha(1), d(1), theta(1)+beta(1)); T2 = DH(2, a(2), alpha(2), d(2), theta(2)+beta(2)); T3 = DH(3, a(3), alpha(3), d(3), theta(3)+beta(3)); T4 = DH(4, a(4), alpha(4), d(4), theta(4)+beta(4)); T = T1 * T2 * T3 * T4; delta_a = 0.001; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, a(i), 1) * delta_a; end for i = 1:4 delta_T = delta_T + diff(T, a(i), 1) * delta_a; end delta_alpha = 0.003; for i = 1:4 delta_T = delta_T + diff(T, alpha(i), 1) * delta_alpha; end delta_d = 0.005; for i = 1:4 delta_T = delta_T + diff(T, d(i), 1) * delta_d; end delta_theta = 0.02*du; for i = 1:4 delta_T = delta_T + diff(T, theta(i), 1) * delta_theta; end delta_beta = 0.0; for i = 1:4 delta_T = delta_T + diff(T, beta(i), 1) * delta_beta; end q = [theta(1), 0, theta(3), theta(4)]; T = Needle.fkine(q); pos = T(1:3, 4); euler = tr2eul(T, 'ZYX')/du; delta_pos = delta_T(1:3, 4); delta_euler = tr2eul(delta_T, 'ZYX')/du;错误使用 diff 差分阶数 N 必须为正整数标量。 出错 ceshi (line 21) delta_T = delta_T + diff(T, a(i), 1) * delta_a; 怎么使用这个查分结束N ,一直报错

2023-06-02 上传

clear all; clc; du = pi/180; a = [0+0.001, 185+0.0079, 0+0.005, 120+0.12]; alpha = [pi/2+0.003, 0+0.001, pi/2+0.005, pi/2]; d = [0+0.001, 0+0.0079, 90+0.005, 0+0.12]; theta = [90du+0.02, 0, 0.023, 0.08]; beta = zeros(1, 4)+0; L1(1) = Link('d', d(1), 'a', a(1), 'alpha', alpha(1), 'qlim', [180du, 365du], 'modified'); L1(2) = Link('d', d(2), 'a', a(2), 'alpha', alpha(2), 'qlim', [3du, 63du], 'modified'); L1(3) = Link('d', d(3), 'a', a(3), 'alpha', alpha(3), 'qlim', [60du, 120du], 'modified'); L1(4) = Link('d', d(4), 'a', a(4), 'alpha', alpha(4), 'qlim', [230du, 326du], 'modified'); Needle = SerialLink(L1, 'name', 'Needle'); T1 = DH(1, a(1), alpha(1), d(1), theta(1)+beta(1)); T2 = DH(2, a(2), alpha(2), d(2), theta(2)+beta(2)); T3 = DH(3, a(3), alpha(3), d(3), theta(3)+beta(3)); T4 = DH(4, a(4), alpha(4), d(4), theta(4)+beta(4)); T = T1T2T3T4; delta_a = 0.001; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, a(i))*delta_a; end delta_alpha = 0.003; for i = 1:4 delta_T = delta_T + diff(T, alpha(i))*delta_alpha; end delta_d = 0.005; for i = 1:4 delta_T = delta_T + diff(T, d(i))delta_d; end delta_theta = 0.02du; for i = 1:4 delta_T = delta_T + diff(T, theta(i))*delta_theta; end delta_beta = 0.0; for i = 1:4 delta_T = delta_T + diff(T, beta(i))*delta_beta; end q = [theta(1), 0, theta(3), theta(4)]; T = Needle.fkine(q); pos = T(1:3, 4); euler = tr2eul(T, 'ZYX')/du; delta_pos = delta_T(1:3, 4); delta_euler = tr2eul(delta_T, 'ZYX')/du;上段代码显示错误使用 diff 差分阶数 N 必须为正整数标量。 出错 ceshi2 (line 28) delta_T = delta_T + diff(T, a(i))*delta_a;

2023-06-02 上传

clear all; clc; du = pi/180; L1(1) = Link('theta', 90*du+0.02, 'a', 0+0.001, 'alpha', 0+0.003, 'qlim', [180, 365], 'modified'); L1(2) = Link('d', 0+0.001, 'a', 185+0.0079, 'alpha', 0+0.001, 'qlim', [3*du, 63*du], 'modified'); L1(3) = Link('d', 90+0.005, 'a', 0+0.005, 'alpha', pi/2+0.005, 'qlim', [60*du, 120*du], 'modified'); L1(4) = Link('theta', 0, 'a', 120+0.12, 'alpha', pi/2, 'qlim', [230, 326], 'modified'); L1(3).theta = L1(3).theta + 0.023; L1(4).theta = L1(4).theta + 0.08; Needle = SerialLink(L1, 'name', 'Needle'); a = [0+0.001, 185+0.0079, 0+0.005, 120+0.12]; alpha = [0+0.003, 0+0.001, pi/2+0.005, pi/2]; d = [0+0.001, 90+0.005, 0+0.005, 0]; theta = [90*du+0.02, 0, L1(3).theta, L1(4).theta]; beta = zeros(1, 4); T1 = DH(1, a(1), alpha(1), d(1), theta(1)+beta(1)); T2 = DH(2, a(2), alpha(2), d(2), theta(2)+beta(2)); T3 = DH(3, a(3), alpha(3), d(3), theta(3)+beta(3)); T4 = DH(4, a(4), alpha(4), d(4), theta(4)+beta(4)); T = T1*T2*T3*T4; delta_T = diff(T, a)*delta_a; delta_T = diff(T, alpha)*delta_alpha; delta_T = diff(T, d)*delta_d; delta_T = diff(T, theta)*delta_theta; delta_T = diff(T, beta)*delta_beta; delta_a = 0.001; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, a(i))*delta_a; end delta_alpha = 0.003; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, alpha(i))*delta_alpha; end delta_d = 0.005; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, d(i))*delta_d; end delta_theta = 0.02*du; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, theta(i))*delta_theta; end delta_beta = 0.0; delta_T = zeros(4, 4); for i = 1:4 delta_T = delta_T + diff(T, beta(i))*delta_beta; end q = [90*du, 0, L1(3).theta, L1(4).theta]; T = Needle.fkine(q); pos = T(1:3, 4) euler = tr2eul(T, 'ZYX')/du delta_pos = delta_T(1:3, 4) delta_euler = tr2eul(delta_T, 'ZYX')/du这段代码运行不出来显示T超出数组元素

2023-06-02 上传

clear all; clc; du = pi/180; a = [0+0.001, 185+0.0079, 0+0.005, 120+0.12]; alpha = [pi/2+0.003, 0+0.001, pi/2+0.005, pi/2]; d = [0+0.001, 0+0.0079, 90+0.005, 0+0.12]; theta = [90*du+0.02, 0, 0.023, 0.08]; L1(1) = Link('d', d(1), 'a', a(1), 'alpha', alpha(1), 'qlim', [180*du, 365*du], 'modified'); L1(2) = Link('d', d(2), 'a', a(2), 'alpha', alpha(2), 'qlim', [3*du, 63*du], 'modified'); L1(3) = Link('d', d(3), 'a', a(3), 'alpha', alpha(3), 'qlim', [60*du, 120*du], 'modified'); L1(4) = Link('d', d(4), 'a', a(4), 'alpha', alpha(4), 'qlim', [230*du, 326*du], 'modified'); Needle = SerialLink(L1, 'name', 'Needle'); % 输入四个关节角度值 theta = [30*du, 45*du, 60*du, 75*du]; % 计算正解得到末端位姿 T1 = DH(1, a(1), alpha(1), d(1), theta(1)); T2 = DH(2, a(2), alpha(2), d(2), theta(2)); T3 = DH(3, a(3), alpha(3), d(3), theta(3)); T4 = DH(4, a(4), alpha(4), d(4), theta(4)); T = T1 * T2 * T3 * T4; % Step 2:利用微分变换原理计算机器人各个连杆机构之间的微小原始偏差 delta_a = 0.001; % a参数的微小偏差 delta_alpha = 0.001; % alpha参数的微小偏差 delta_d = 0.001; % d参数的微小偏差 delta_theta = 0.001; % theta参数的微小偏差 delta_T1 = DH(1, a(1)+delta_a, alpha(1), d(1), theta(1)) - T1; delta_T2 = DH(2, a(2)+delta_a, alpha(2), d(2), theta(2)) - T2; delta_T3 = DH(3, a(3)+delta_a, alpha(3), d(3), theta(3)) - T3; delta_T4 = DH(4, a(4)+delta_a, alpha(4), d(4), theta(4)) - T4; % Step 3:计算误差矩阵 delta_T = delta_T1 * delta_T2 * delta_T3 * delta_T4; % Step 4:将误差矩阵转化为误差值 delta_x = delta_T(1,4); delta_y = delta_T(2,4); delta_z = delta_T(3,4); % 输出末端位姿误差 fprintf('末端位姿误差:\n'); fprintf('Delta x: %.6f mm\n', delta_x*1000); fprintf('Delta y: %.6f mm\n', delta_y*1000); fprintf('Delta z: %.6f mm\n', delta_z*1000);为什么我得到位姿矩阵为0,derta_T各行各列都是0

2023-06-02 上传