Objective-C编程第6版：开发者的必备参考

Objective-C,

iOS

需积分: 10 128 浏览量更新于2024-07-24 收藏 4.17MB PDF 举报

身份认证购VIP最低享 7 折!

30元优惠券

资源详情

资源推荐

ptg11524036

Contents

III: Cocoa, Cocoa Touch, and the iOS SDK

20 Introduction to Cocoa and Cocoa Touch 449

Framework Layers 449

Cocoa Touch 450

21 Writing iOS Applications 453

The iOS SDK 453

Your First iPhone Application 453

Creating a New iPhone Application Project 456

Entering Your Code 460

Designing the Interface 462

An iPhone Fraction Calculator 469

Starting the New Fraction_Calculator Project 471

Defining the View Controller 471

The

Fraction Class 477

Calculator Class That Deals with Fractions 480

Designing the User Interface 482

Summary 483

Exercises 484

Appendixes

A Glossary 485

B Address Book Example Source Code 493

Index 499

Kochan.indb xv 11/12/13 7:43 AM

ptg11524036

Introduction

Dennis Ritchie at AT&T Bell Laboratories pioneered the C programming language in the early

1970s. However, this programming language did not begin to gain widespread popularity and

support until the late 1970s. This was because, until that time, C compilers were not readily

available for commercial use outside of Bell Laboratories. Initially, this growth in popularity

was also partly spurred by the equal, if not faster, growth in popularity of the UNIX operating

system, which was written almost entirely in C.

Brad J. Cox designed the Objective-C language in the early 1980s. The language was based on a

language called SmallTalk-80. Objective-C was layered on top of the C language, meaning that

extensions were added to C to create a new programming language that enabled objects to be

created and manipulated.

NeXT Software licensed the Objective-C language in 1988 and developed its libraries and

a development environment called NEXTSTEP. In 1992, Objective-C support was added to

the Free Software Foundation’s GNU development environment. The copyrights for all Free

Software Foundation (FSF) products are owned by the FSF. It is released under the GNU General

Public License.

In 1994, NeXT Computer and Sun Microsystems released a standardized specification of

the NEXTSTEP system, called OPENSTEP. The FSF’s implementation of OPENSTEP is called

GNUStep. A Linux version, which also includes the Linux kernel and the GNUStep develop-

ment environment, is called, appropriately enough, LinuxSTEP.

On December 20, 1996, Apple Computer announced that it was acquiring NeXT Software, and

the NEXTSTEP/OPENSTEP environment became the basis for the next major release of Apple’s

operating system, OS X. Apple’s version of this development environment was called Cocoa.

With built-in support for the Objective-C language, coupled with development tools such as

Project Builder (or its successor Xcode) and Interface Builder, Apple created a powerful develop-

ment environment for application development on Mac OS X.

In 2007, Apple released an update to the Objective-C language and labeled it Objective-C 2.0.

That version of the language formed the basis for the second edition of the book.

Kochan.indb 1 11/12/13 7:43 AM

剩余550页未读，继续阅读

Valency

粉丝: 0
资源: 1

Objective-C编程第6版：开发者的必备参考

Programming in Objective-C, 第四版，ePub格式

高清彩版 Programming in Objective-C(6th)

programming in objective-c six edition

programming in objective-c中文

Objective-C

swiftui object-c对比

Swift XCFramework

x=linprog(-c,a,b,aeq,beq,zeros(3,1))

c=[-10,-9]; A=[6 5;10 20;1 0]; b=[60;150;8]; vlb=zeros(2,1); Aeq=[]; beq=[]; vub=[]; [x,fval]=linprog(c,A,b,Aeq,beq,vlb,vub);

print（%s）怎么用

Please use one of the HiGHS solvers (e.g. `method='highs'`) in new code.

圈养湖羊的空间利用率数学建模

分别用LINGO和MATLAB进行编程求解。maxf(X)=4*x1-x1*x1+9*x2-x2*x2+10*x3-2*x3*x3-(1/2)*x2*x3 s.t.{4*x1+2*x2+x3<=10; 2*x1+4*x2+x3<=20;x1,x2,x3>=0}

请写一段整数规划求解器的python代码，要求循环定义n个变量，变量取值为0或1

求解标准形式线性规划问题的单纯形方法matlab程序

根据割平面法原理编写对应的Python代码，得到一个割平面法整数规划求解器

Python 实现整数线性规划：分枝定界法（Branch and Bound）

python单纯形法代码

用python写一个不用对偶算法的线性规划迭代法

利用python进行构建线性规划模型的步骤，设计参数值以及结果解读

最新资源

分别用LINGO和MATLAB进行编程求解。maxf(X)=4x1-x1x1+9x2-x2x2+10x3-2x3x3-(1/2)x2x3 s.t.{4x1+2x2+x3<=10; 2x1+4*x2+x3<=20;x1,x2,x3>=0}